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Theo mình thì phân tích ra thành thế này
gọi số cần tìm là \(ab\) có:
\(ab=x^3;a+b=x^2\)(\(x\) là số tự nhiên mà khi lập phương lên thì bằng \(ab\), khi bình phương lên thì bằng \(a+b\))
Từ đó ta có: \(10a+b=x^3\)
\(a+b=x^2\)
Rồi suy ra được ab thì phải, mình không biết có đúng không nữa, nếu mà các bước mình làm đúng thì bạn nghiên cứu thêm nhé
gọi a,b,c là 3 số tự nhiên phải tìm
Ta có : \(\frac{a}{b}=\frac{2}{3}\); \(\frac{b}{c}=\frac{5}{6}\)
\(\Rightarrow a=\frac{2}{3}b;c=\frac{6}{5}b\)
Mà a2 + b2 + c2 = 2596 nên \(\frac{4}{9}b^2+b^2+\frac{36}{25}b^2=2596\)
hay \(\frac{649}{225}b^2=2596\)\(\Rightarrow\)b2 = 900
\(\Rightarrow\orbr{\begin{cases}b=30\\b=-30\end{cases}}\)
Từ đó suy ra : \(\orbr{\begin{cases}a=20\\a=-20\end{cases}}\); \(\orbr{\begin{cases}c=36\\c=-36\end{cases}}\)
Vậy ...
Gọi số đó là \(\overline{ab}\) (a,b là chữ số; a khác 0)
Theo bài ra ta có:
\(\overline{ab}+210=\overline{a3b}\\ \\ \Rightarrow a.10+b+210=a.100+30+b\\ \\ \Rightarrow210-30=a.100-a.10\\ \\ \Rightarrow180=a.90\Rightarrow a=180:90=2\)
Do a+b=9 (theo đề bài) ⇒ b=7⇒\(\overline{ab}=27\)
Vậy số cần tìm là 27
a) goi hai so la a ; b va a >b
vi UCLN(a,b)=18=>a=18k ; b=18q (trong do UCLN (k,q)=1 va k>q)
=>a+b=162
18k+18q =162
18(k+q)=162
k+q=9
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