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\(A=\left[\frac{1\frac{11}{31}\cdot4\frac{3}{7}-\left(15-6\frac{1}{3}\cdot\frac{2}{19}\right)}{4\frac{5}{6}+\frac{1}{6}\left(12-5\frac{1}{3}\right)}\cdot\left(-1\frac{14}{93}\right)\right]\cdot\frac{31}{50}\)
\(A=\left[\frac{\frac{42}{31}\cdot\frac{31}{7}-\left(15-\frac{19}{3}\cdot\frac{2}{19}\right)}{4\frac{5}{6}+\frac{1}{6}\left(12-\frac{16}{3}\right)}\cdot\left(-\frac{107}{93}\right)\right]\cdot\frac{31}{50}\)
\(A=\left[\frac{6-\left(15-\frac{2}{3}\right)}{\frac{29}{6}+\frac{10}{9}}\cdot\left(-\frac{107}{93}\right)\right]\cdot\frac{31}{50}\)
\(A=\left[\frac{6-\frac{43}{3}}{\frac{107}{18}}\cdot\left(-\frac{107}{93}\right)\right]\cdot\frac{31}{50}\)
\(A=\left[\frac{-\frac{25}{3}}{\frac{107}{18}}\cdot\left(-\frac{107}{93}\right)\right]\cdot\frac{31}{50}\)
\(A=\frac{50}{31}\cdot\frac{31}{50}=1\)
\(\left(-\frac{3}{7}+\frac{5}{11}\right):\frac{4}{31}+\left(-\frac{4}{7}+\frac{6}{11}\right):\frac{4}{31}\)
\(=\left(-\frac{3}{7}+\frac{5}{11}\right)\cdot\frac{31}{4}+\left(-\frac{4}{7}+\frac{6}{11}\right)\cdot\frac{31}{4}\)
\(=-\frac{3}{7}\cdot\frac{31}{4}+\frac{5}{11}\cdot\frac{31}{4}-\frac{4}{7}\cdot\frac{31}{4}+\frac{6}{11}\cdot\frac{31}{4}\)
\(=\frac{31}{4}\cdot\left(-\frac{3}{7}-\frac{4}{7}+\frac{5}{11}+\frac{6}{11}\right)\)
\(=\frac{31}{4}\cdot\left(-1+1\right)\)
\(=\frac{31}{4}\cdot0\)
\(=0\)
mk làm khác bạn