help me

help me

a = 48/6 - 15/6 = 33/6 = 11/3

b = 52/17 - 51/17 = 1/17 

làm hộ

\(\dfrac{4^5\cdot9^4-2\cdot6^9}{2^{10}\cdot3^8+6^8\cdot20}=\dfrac{2^{10}\cdot3^8-2\cdot2^9\cdot3^8\cdot3}{2^{10}\cdot3^8+2^8\cdot3^8\cdot2^2\cdot5}=\dfrac{2^{10}\cdot3^8-2^{10}\cdot3^9}{2^{10}\cdot3^8+2^{10}\cdot3^8\cdot5}\)

\(=\dfrac{2^{10}\cdot3^8\left(1+3\right)}{2^{10}\cdot3^8\left(1+5\right)}=\dfrac{4}{6}=\dfrac{2}{3}\)

`1/3-2/15+14/15`

`=5/15-2/15+14/15`

`=17/15`

`3/5+4-6/7`

`=21/35+140/35-30/35`

`=131/35`

giúp mình với ạ, thanks!

Ta có:

\(\dfrac{a^2-ab+b^2}{a^2+ab+b^2}=\dfrac{\dfrac{1}{3}\left(a^2+ab+b^2\right)+\dfrac{2}{3}\left(a-b\right)^2}{a^2+ab+b^2}\)

\(=\dfrac{1}{3}+\dfrac{2\left(a-b\right)^2}{3\left(a^2+ab+b^2\right)}\ge\dfrac{1}{3}\)

Dấu = xảy ra khi \(a=b\)

`6:2xx(1+2)`

`= 6:2 xx 3`

`=3 x 3`

`=9`

ấn máy tính là 9 nên xóa

chắc là chia trước