EX 2:
1. Stop fooling around! I am trying to concentrate
2. Look! It is snowing
3. Why are you looking at me like that? Did I say something wrong
4. You are making a lot of noise. Can you be a little bit quieter
5. Excuse me, I am looking for a phone booth. Is there one near here
6. Can you hear those people next door? They are yelling at each other again
7. Why are you wearing your shorts today? It’s very cold
8. I am not working this week. I’m on vacation
9. I want to lose weight. I am not eating anything today
10. Listen to those people. What language are they speaking

Ex 3:
1. His wife always agrees with everything he says
2. This book belongs to me
3. His father owns a chain of hotels
4. Money doesn’t matter to me
5. That bottle contains petrol
6. I realize that I’ve made a mistake
7. Do you mind if I open a window
8. I believe it’s time to go home
9. “He’s a great president.” – “I don’t agree
10. Let’s buy these cushions. They feel so soft

Exercise 2: Put the verb into the correct form, using present continuous.

1. Stop fooling around! I (try) ____am trying____________ to concentrate.

2. Look! It (snow) _____is snowing___________.

3. Why (you/look) ______are you looking__________ at me like that? Did I say something wrong?

4. You (make) ________are making________ a lot of noise. Can you be a little bit quieter?

5. Excuse me, I (look) ______am looking __________ for a phone booth. Is there one near here?

6. Can you hear those people next door? They (yell) ______are yelling__________ at each other again.

7. Why (you/wear) ________are you wearing________ your shorts today? It’s very cold.

8. I (not/work) _____am not working___________ this week. I’m on vacation.

9. I want to lose weight. I (not/eat) ____am not eating____________ anything today.

10. Listen to those people. What language (they/speak) __________are they speaking______?

S = 155\(\times\)\(\overline{710y4z16}\)\(⋮\) 33

Vì 155 không chia hết cho 33 nên S ⋮ 33 ⇔ \(\overline{710x4y16}\) ⋮ 33

           33 = 3.11 Vì (3; 11) = 1

Nên  \(\overline{710x4y16}\) ⋮ 33 ⇔ \(\overline{710x4y16}\) ⋮ 3; 11

        ⇒ \(\left\{{}\begin{matrix}7+0+4+1=1+x+y+6\\7+1+0+x+4+y+1+1⋮3\end{matrix}\right.\)

        ⇒ \(\left\{{}\begin{matrix}x+y=5\\19+x+y⋮3\end{matrix}\right.\)

          ⇒ \(x+y\) = 5

Lập bảng ta có:

Theo bảng trên ta có:

(\(x\);y) = (0;5); (1; 4); (2; 3); (3; 2); (4; 1); (0; 5)

\(\dfrac{a}{a+b}+\dfrac{b}{b+c}+\dfrac{c}{c+a}>\dfrac{a}{a+b+c}+\dfrac{b}{a+b+c}+\dfrac{c}{a+b+c}=1\)

\(\dfrac{a}{a+b}+\dfrac{b}{b+c}+\dfrac{c}{c+a}< \dfrac{a+c}{a+b+c}+\dfrac{b+a}{b+c+a}+\dfrac{c+b}{a+b+c}=\dfrac{2\left(a+b+c\right)}{a+b+c}=2\)

\(\Rightarrow1< \dfrac{a}{a+b}+\dfrac{b}{b+c}+\dfrac{c}{c+a}< 2\)

Giải nhanh giúp mik nhé,mai mình nộp r !

Chim cánh cụt là loài sống theo quần thế, có tính xã hội cao, luôn tập trung theo bầy đàn.

Nhưng tập tính ;à của sách Khoa học tự nhiên mà bạn?

Nếu như là đúng như vậy thì bạn chú ý để đúng lớp nhé!

Cây 1 và cây 2 cách nhau : \(12m\)

Cần trồng thêm:

\(\dfrac{12}{3}-1=3\left(cây\right)\)

Cây 2 và cây 3 cách nhau: \(6m\)

Cần trồng thêm:

\(\dfrac{6}{3}-1=1\left(cây\right)\)

Cây 3 và cây 4 cách nhau: \(15m\)

Cần trồng thêm:

\(\dfrac{15}{3}-1=4\left(cây\right)\)

 Vậy số cây hoa sữa cần trồng thêm ít nhất để khoảng cách giữa hai cây liên tiếp bằng nhau là:

\(3+1+4=8\left(cây\right)\)

Đáp số: \(8\) cây.

Gọi số điểm là \(x\).

Nếu giảm đi \(1\) điểm, số đường thẳng bị giảm đi là \(x-1\).

Nếu giảm tiếp đi \(1\) điểm, số đường thẳng bị giảm đi thêm là \(x-1-1=x-2\).

Lại có, nếu bỏ đi \(2\) điểm, số đường thẳng bị giảm đi là \(25\).ư

\(\Rightarrow x-1+x-2=25\)

\(\Rightarrow x\times2=25+1+2\)

\(\Rightarrow x\times2=28\)

\(\Rightarrow x=28:2\)

\(\Rightarrow x=14\)

Vậy ban đầu có \(14\) điểm.