1. informative

2. machiner

3. injury 

4. appeared

5. please

6. experienced

7. succeeded

8. variety

Give the correct form of the word given in bracket:

1, We watch the news everyday because it's very ..........information...................                          INFORM

2, Mr Jone repairs machines in a factory. He is a ........machiner.......................                         MACHINE

3, Lan fell off the bike, but her ..........injury..................were not serious.                               INJURE

4, We couldn't see the airplane because it ........appeared.................. behind the cloud.             APPEAR   

5, l travelling by motorbike, but it's .....please...................... in bad weather.                     PLEASE

6, You'd better drive. I'm too ...........EXPERIENCED.................. for such complicated traffic.                EXPERIENCE

7, Although he tried his best to do it, he was ............SUCCESSED.............. .                                     SUCESS

8, There is a ..........variety.................. of food in this supermarket.                                           VARY

My sister s badminton but she doesn’t play it very good.
      => well                                         
You’d better taking off your wet overcoat and those muddy shoes before going home.
         => take                
I’ll give you some medicine to make you to feel better.
         => X
Each student have to write a paragraph about the benefits of learning English
     => has             
We will be there for about twenty – five minutes.
                 
He was absent for work because of illness
      => the illness
Who is the good at Maths in your class?
      => X                   
You ought to not go out without a coat. It’s cold outside.
         =>    not to           
The telephone sounds badly because of the bad weather.
          => bad      
We are looking forward to hear from my mother in Singapore.

=> hearing 

mk làm lại đây nhé:

My sister s badminton but she doesn’t play it very good.
      => well                                         

You’d better taking off your wet overcoat and those muddy shoes before going home.
         => take                
I’ll give you some medicine to make you to feel better.
         => X

Each student have to write a paragraph about the benefits of learning English
     => has             

We will be there for about twenty – five minutes.
                 

He was absent for work because of illness
      => the illness

Who is the good at Maths in your class?
      => X                   

You ought to not go out without a coat. It’s cold outside.
         =>    not to           

The telephone sounds badly because of the bad weather.
          => bad      

We are looking forward to hear from my mother in Singapore.

=> hearing 

Trả lời :

\(NSF_3\) – Thiazyl triflorua

\(ClO\) – Clo monoxit

\(C_2N_2\) – Xyano

\(CO\) – Cacbon monoxit

\(NO\) – Nitric oxit

\(N_2O\) – Nitrơ oxit (khí bóng cười)

\(C_6H_6\) – Benzen

\(C_6H_5CN\) – Benzonitril

\(BeCl_2\) – Beri clorua

Trả lời:

Khi cho kim loại kiềm vào dd axit thì kim loại kiềm sẽ phản ứng với H₂O trước do các kim loại kiềm có tính khử mạnh.

~HT~

kim loại kiềm dư tác dụng với dung dịch axit thì phản ứng H₂O trước nha bạn 

K nha !

Mg + H₂SO₄ -------> MgSO₄ + H₂

MgSO₄ + BaCl₂ --------> MgCl₂ + BaSO₄

MgCl₂ + 2KNO₃ -------> 2KCl + Mg(NO₃)₂

Mg(NO₃)₂ + 2NaOH ------> Mg(OH)₂ + 2NaNO₃

Mg(OH)₂ --------> MgO + H₂O

MgO + H₂SO₄ -------> MgSO₄ + H₂O

\(MgCl_2\rightarrow Mg+Cl_2\uparrow\)

\(2Mg+O_2\rightarrow2MgO\)

\(MgO+H_2SO_4\rightarrow MgSO_4\downarrow+H_2O\)

\(MgSO_4+Ba\left(NO_3\right)2\rightarrow Mg\left(NO_3\right)_2+BaSO_4\downarrow\)

\(Mg\left(NO_3\right)_2+2NaOH\rightarrow Mg\left(OH\right)_2\downarrow+2NaNO_3\)

\(Mg\left(OH\right)_2\rightarrow MgO+H_2O\)

gọi số hạt proton ,nơtron và electron của nt kim loại A là P1;N1 và E1

gọi số hạt proton ,nơtron và electron của nt kim loạiB là P2;N2;E2

Theo đb ta có :P1+N1+E1+P2+N2+E2=142 VÀ (P1+E1+P2+E2)-(N1+N2)=42

=> (P1+E1+P2+E2)=(142+42):2=92

Ta lại có:(P2+E2)-(P1+E1)=12

=>P2+E2=(92+12):2=52 VÌ SỐ P=E NÊN P2=E2=52/2=26

=>P1+E1=52-12=40 VÌ SỐ P=E NÊN P1=E1 =40/2=20

P2 = 26

P1 = 20

K nhé

Tại sao lại có 142+42

\(CuO+H_2SO_4\rightarrow CuSO_4+H_2O\)

\(m_{H_2SO_4}=\frac{98.30}{100}=29,4g\)

\(\rightarrow n_{H_2SO_4}=\frac{29,4}{98}=0,3mol\)

a. Theo phương trình \(n_{CuO}=n_{H_2SO_4}=0,3mol\)

\(\rightarrow m=m_{CuO}=0,3.\left(64+16\right)=24g\)

b. Theo phương trình \(n_{CuSO_4}=n_{H_2SO_4}=0,3mol\)

\(\rightarrow m_{CuSO_4}=0,3.\left(64+32+16.4\right)=48g\)

\(m_{ddsaupu}=m_{CuO}+m_{ddH_2SO_4}=24+98=122g\)

\(\rightarrow C\%_{CuSO_4}=\frac{48.100}{122}=39,34\%\)

Đặt \(\hept{\begin{cases}x=n_{CuO}\\y=n_{Al_2O_3}\end{cases}}\)

PTHH: \(CuO+2HCl\rightarrow CuCl_2+H_2O\)

\(Al_2O_3+6HCl\rightarrow2AlCl_3+3H_2O\)

Theo phương trình \(\hept{\begin{cases}x=n_{CuCl_2}\\2y=n_{AlCl_3}\end{cases}}\)

\(\rightarrow135x+133,5.2y=4,02\left(1\right)\)

\(n_{HCl}=0,8.0,1=0,08mol\)

\(\rightarrow2x+6y=0,08\left(2\right)\)

Từ (1) và (2) => x = y = 0,01 mol

\(\rightarrow\%m_{CuO}=\frac{0,01.80}{0,01.80+0,01.102}.100\%=43,96\%\)

\(\rightarrow\%m_{Al_2O_3}=100-43,96\%=56,04\%\)

Đặt:\(\hept{\begin{cases}x=n_{CuO}\\y=n_{al_2O_3}\end{cases}}\)

PTHH:\(CuO+2HCL\rightarrow CuCl_2+H_2O\)

\(Al_2O_3+6HCL\rightarrow2Alcl_3+3H_2O\)

Theo phương trình: \(\hept{\begin{cases}x=n_{CuCl_2}\\2y=n_{AlCl_3}\end{cases}}\)

\(\rightarrow135x+133,5\cdot2y=4,02\left(1\right)\)

\(n_{HCL}=0,8\cdot0,1=0,08mol\)

\(\rightarrow2x+6y=0,08\left(2\right)\)

\(\Rightarrow x=y=0,01mol\)

\(\rightarrow\%m_{CuO}=\frac{0,01\cdot80}{0,01\cdot80+0,01\cdot102}\cdot100=43,96\%\)

\(\rightarrow\%m_{al_2O_3}=100\%-43,96\%=56,04\%\)

??? đề bài đâu dợ ?