x: (2x -1) . (5x+3/4) =0  đk x # 1/2

⇔ x = 0 hoăc 5x + 3/4 = 0⇒ x = -3/4: 5 = -3/20

vậy x = {-3/20; 0}

`(2/3x - 1) . (5x + 3/4) = 0`

`=>` \(\left[{}\begin{matrix}\dfrac{2}{3}x-1=0\\5x+\dfrac{3}{4}=0\end{matrix}\right.\)

`=>` \(\left[{}\begin{matrix}\dfrac{2}{3}x=0+1\\5x=0-\dfrac{3}{4}\end{matrix}\right.\)

`=>` \(\left[{}\begin{matrix}\dfrac{2}{3}x=1\\5x=-\dfrac{3}{4}\end{matrix}\right.\)

`=>` \(\left[{}\begin{matrix}x=1:\dfrac{2}{3}\\x=-\dfrac{3}{4}:5\end{matrix}\right.\)

`=>` \(\left[{}\begin{matrix}x=\dfrac{3}{2}\\x=-\dfrac{3}{20}\end{matrix}\right.\)

Vậy......

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no

Có: \(28=2^2.7\)

\(56=2^4.7\)

\(72=2^3.3^2\)

\(ƯCLN\left(28;56;72\right)=2^2=4\)

2x-2=x

2x=x+2

2x-x=x+2-x

x=2

đúng thì tick cho mình nhé

`|-x+5|=35`

`@TH1:`

`-x+5=35`

`=> -x = 35-5`

`=> -x=-40`

Vậy `-x=-40`

`@TH2:`

`-x+5=35`

`=> -x=35-5`

`=> -x=30(loại)`

Vậy `x = -40`

\(\overline{abc}.\overline{abca}=\overline{abcabc}\)

\(\Rightarrow\overline{abc}.\left(10.\overline{abc}+a\right)=\overline{abc}.1001\)

\(\Rightarrow10.\overline{abc}+a=1001\)

\(\Rightarrow10.\overline{abc}=1001-a⋮10\Rightarrow a=1\)

\(\Rightarrow10.\overline{1bc}=1000\)

\(\Rightarrow10.\left(100+\overline{bc}\right)=1000\)

\(\Rightarrow1000+10.\overline{bc}=100\Rightarrow\overline{bc}=0\)

\(\Rightarrow\overline{abc}=100\)

a/

\(\left(2x+1\right)^3=125=5^3\)

\(\Rightarrow2x+1=5\Rightarrow x=2\)

b/

\(64.4^x=4^5\Leftrightarrow4^3.4^x=4^5\)

\(\Leftrightarrow4^{x+3}=4^5\Rightarrow x+3=5\Rightarrow x=2\)

`(2x+1)^3 = 125

`(2x+1)^3 = 5^2`

`2x+1=5`

`2x=5-1`

`2x=4`

`x=4:2`

`x=2`

Vậy `x = 2`

_____________________________

`64.4^x = 4^5`

`4^x  = 4^5 : 64`

`4^x = 4^5 : 4^3`

`4^x= 4^2`

`=> x = 2`

1233; 1323; 1332; 2133; 2313; 2331; 3123; 3132; 3213; 3231; 3312; 3321

1233; 1323; 1332; 2133; 2313; 2331; 3123; 3132; 3213; 3231; 3312; 3321