ai giúp mik với ak mik cần gấp

\(\dfrac{1}{1.4}+\dfrac{1}{4.2}+\dfrac{1}{2.8}+\dfrac{1}{8.4}+\dfrac{1}{4.16}+\dfrac{1}{16.8}\)

= \(\dfrac{1}{4}.\left(1+\dfrac{1}{2}+\dfrac{1}{4}+\dfrac{1}{8}+\dfrac{1}{16}+\dfrac{1}{32}\right)\)

= \(\dfrac{1}{4}.\left(\dfrac{3}{2}+\dfrac{3}{8}+\dfrac{3}{32}\right)\)

= \(\dfrac{1}{4}.\dfrac{3}{2}\left(1+\dfrac{1}{4}+\dfrac{1}{16}\right)\)

= \(\dfrac{1}{4}.\dfrac{3}{2}\left(\dfrac{16}{16}+\dfrac{4}{16}+\dfrac{1}{16}\right)\)

= \(\dfrac{3}{8}.\dfrac{21}{16}\)

= \(\dfrac{63}{128}\)

`@` `\text {Ans}`

`\downarrow`

`100 - 2(x - 4) = 20`

`=> 2(x - 4) = 100 - 20`

`=> 2(x - 4) = 80`

`=> x - 4 = 80 \div 2`

`=> x - 4 = 40`

`=> x = 40 + 4`

`=> x = 44`

Vậy, `x = 44.`

`@` `\text {Kaizuu lv uuu}`

100 - 2(x-4) = 20

⇒ 2(x-4)= 100-20=80

⇒ x-4 = 80:2 = 40

⇒ x= 40+4=44

cứu

Tỉ số phần trăm của 15 k và 120 k là:

          15 : 120 = 0,125 

          0,125 = 12,5%

Giá trị của 4 dấu ? là 12,5% 

Viết kết quả dưới dạng luỹ thừa thì phép tính này bằng \(a^{1000}\) nhé.

\(3^3\cdot3^4\cdot3^5\)

\(=3^{3+4+5}\)

\(=3^{12}\)

$3^3\cdot 3^4\cdot 3^5$

$=3^{3+4+5}$

$=3^{12}$

\(\dfrac{2}{5}-9-\dfrac{7}{2}\)

\(=\dfrac{2}{5}-\dfrac{9}{1}-\dfrac{7}{2}\)

\(=\left(\dfrac{2}{5}-\dfrac{9}{1}\right)-\dfrac{7}{2}\)

\(=\left(\dfrac{2}{5}-\dfrac{45}{5}\right)-\dfrac{7}{2}\)

\(=-\dfrac{43}{5}-\dfrac{7}{2}\)

\(=-\dfrac{86}{10}-\dfrac{35}{10}\)

\(=-\dfrac{121}{10}\)

Vì (x−7)(x+3)<0

⇒x−7>0; x+3<0

   x−7<0; x+3>0

⇒x>7;x<−3

   x<7;x>−3

⇒−3<x<7

Vậy −3<x<7

Vì 4<n≤7 và nϵN

⇒ n ϵ {5;6;7}

⇒ K=(n-1).(2n-1) ϵ {36;55;78}

\(3^8\cdot2^7\)

\(=3^7\cdot2^7\cdot3\)

\(=\left(3\cdot2\right)^7\cdot3=6^7\cdot3\)

\(=839808\)

\(3^8\times2^7=3^7\times3\times2^7=\left(3\times2\right)^7\times3=6^7\times3\)

\(1-\dfrac{3}{2}+2-\dfrac{5}{2}+...+2003-\dfrac{4007}{2}+2004\)

= \(\left(-\dfrac{1}{2}\right)+\left(-\dfrac{1}{2}\right)+...\left(-\dfrac{1}{2}\right)+2004\)

= \(2003.\left(-\dfrac{1}{2}\right)+2004\)

= \(-\dfrac{4006}{2}+\dfrac{4008}{2}\)

= \(\dfrac{2}{2}\)

= \(1\)