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QN
0
26 tháng 11 2017
\(P=\frac{2x+2}{\sqrt{x}}+\frac{x\sqrt{x}+1}{x-\sqrt{x}}-\frac{x\sqrt{x}+1}{x+\sqrt{x}}\)
\(P=\frac{2x+2}{\sqrt{x}}+\frac{\sqrt{x^3}+1}{\sqrt{x}\left(\sqrt{x}-1\right)}-\frac{\sqrt{x^3}+1}{\sqrt{x}\left(\sqrt{x}+1\right)}\)
\(P=\frac{2x+2}{\sqrt{x}}-\frac{\left(\sqrt{x}+1\right)\left(x-\sqrt{x}+1\right)}{\sqrt{x}\left(\sqrt{x}+1\right)}\)\(-\frac{\left(\sqrt{x}+1\right)\left(x-\sqrt{x}+1\right)}{\sqrt{x}\left(\sqrt{x}+1\right)}\)
\(P=\frac{2x+2}{\sqrt{x}}-\frac{x-\sqrt{x}+1}{\sqrt{x}}-\frac{x-\sqrt{x}+1}{\sqrt{x}}\)
\(P=\frac{2x+2-x+\sqrt{x}-1-x+\sqrt{x}-1}{\sqrt{x}}\)
\(P=\frac{2\sqrt{x}}{\sqrt{x}}\)
\(P=2\)
vậy \(P=2\)
QN
0
QN
0
T
26 tháng 11 2017
PT: \(\hept{\begin{cases}2x^3=y+1\\2y^3=x+1\end{cases}}\)
\(2x^3=y+1\)
\(2x^3=y+1\Leftrightarrow2x^3-1=y\)
\(\Leftrightarrow y=2x^3-1\)
Lấy \(y=2x^3-1\)với \(2y^3=x+1\)
\(2y^3=x+1\)
Đặt \(2\left(2x^3-1\right)^3=x+1\)
1Solve for 2
Expand 3
Simplify to 4
Move all terms to one side 5
Simplify to 6
No root was found algebraically. However, the following root(s) were found by numerical methods.Substitute into How?1 Start with the original equation 2 Let 3 Simplify
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