\(\dfrac{6}{24}-\left(-\dfrac{4}{25}\right)+\dfrac{\left(-8\right)}{32}\)

\(=\dfrac{1}{4}+\dfrac{4}{25}+\dfrac{\left(-1\right)}{4}\)

\(=\left(\dfrac{1}{4}+\dfrac{-1}{4}\right)+\dfrac{4}{25}\)

\(=\dfrac{0}{4}+\dfrac{4}{25}\)

\(=0+\dfrac{4}{25}\)

\(=\dfrac{4}{25}\)

ko bt :)

a: \(\dfrac{1}{2}+\dfrac{1}{3}+\dfrac{1}{6}< =x< =\dfrac{15}{4}+\dfrac{18}{8}\)

=>\(\dfrac{3+2+1}{6}< =x< =\dfrac{15}{4}+\dfrac{9}{4}\)

=>\(\dfrac{6}{6}< =x< =\dfrac{24}{4}\)

=>1<=x<=6

b: \(\dfrac{x+1}{3}=\dfrac{2}{6}\)

=>\(\dfrac{x+1}{3}=\dfrac{1}{3}\)

=>x+1=1

=>x=0

c: \(\dfrac{x+10}{27}=\dfrac{x}{9}\)

=>\(\dfrac{3x}{27}=\dfrac{x+10}{27}\)

=>3x=x+10

=>2x=10

=>x=10:2=5

d: \(\dfrac{1}{2}x+\dfrac{2}{5}x=-\dfrac{18}{25}\)

=>\(x\left(\dfrac{1}{2}+\dfrac{2}{5}\right)=-\dfrac{18}{25}\)

=>\(x\cdot\dfrac{9}{10}=\dfrac{-18}{25}\)

=>\(x=-\dfrac{18}{25}:\dfrac{9}{10}=-\dfrac{18}{25}\cdot\dfrac{10}{9}=\dfrac{-180}{225}=-\dfrac{4}{5}\)

 \(A\in d;C\in d;B\notin d\)

a: \(\dfrac{-5}{19}+\dfrac{2}{19}< \dfrac{x}{19}< =\dfrac{17}{19}-\dfrac{16}{19}\)

=>\(\dfrac{-3}{19}< \dfrac{x}{19}< =\dfrac{1}{19}\)

=>-3<x<=1

mà x nguyên

nên \(x\in\left\{-2;-1;0;1\right\}\)

b: \(\dfrac{4}{5}+\dfrac{-5}{6}< =\dfrac{x}{30}< =\dfrac{-3}{10}+\dfrac{1}{3}\)

=>\(\dfrac{24-25}{30}< =\dfrac{x}{30}< =\dfrac{-9+10}{30}\)

=>\(-1< =x< =1\)

mà x nguyên

nên \(x\in\left\{-1;0;1\right\}\)

đề bài là sao ko hiểu lắm

là tìm số nguyên đểphân số 2n+3/n+1 có giá trị nguyên

\(\dfrac{n+8}{n+5}=\dfrac{n+5+3}{n+5}\\=1+\dfrac{3}{n+5}\)

Để phân số trên nhận gt nguyên thì : \(\dfrac{3}{n+5}\inℤ\) (n nguyên)

=> 3 chia hết cho (n+5)

=> n+5 thuộc Ư(3)={1;-1;3;-3}

=> n thuộc {-4;-6;-2;-8} (thỏa mãn)

Vậy n thuộc {-4;-6;-2;-8} là 4 giá trị nguyên thỏa đề 

Ta có:

n + 8 = n + 5 + 3

Để phân số đã cho nhận giá trị nguyên thì 3 ⋮ (n + 5)

⇒ n + 5 ∈ Ư(3) ={-3; -1; 1; 3}

⇒ n ∈ {-8; -6; -4; -2}

a: \(\dfrac{22}{33}+\dfrac{-444}{555}=\dfrac{2}{3}-\dfrac{4}{5}=\dfrac{10}{15}-\dfrac{12}{15}=-\dfrac{2}{15}\)

b: \(\dfrac{-123}{246}+\dfrac{-131313}{151515}=\dfrac{-1}{2}+\dfrac{-13}{15}\)

\(=\dfrac{-15+\left(-26\right)}{30}=\dfrac{-41}{30}\)

a) 22/33 + (-444/555)

= 2/3 - 4/5

= -2/15

b) -123/246 + (-131313/151515)

= -1/2 - 13/15

= -41/30

a: Đ

b: S

c: Đ

d: S

a: \(\dfrac{-8}{11}+\dfrac{3}{-11}=-1\)

b: \(\dfrac{-30}{44}+\dfrac{-3}{22}< \dfrac{-8}{11}\)

c: \(\dfrac{5}{7}>\dfrac{4}{7}+\dfrac{-1}{7}\)

d: \(\dfrac{2}{3}+\dfrac{-3}{4}< \dfrac{4}{5}+\dfrac{-5}{6}\)

a: sửa đề: \(16\dfrac{3}{5}\cdot\dfrac{7}{9}-13\dfrac{3}{5}\cdot\dfrac{7}{9}\)

\(=\dfrac{7}{9}\left(16+\dfrac{3}{5}-13-\dfrac{3}{5}\right)\)

\(=\dfrac{7}{9}\cdot3=\dfrac{7}{3}\)

b: \(\dfrac{-3}{5}+\left(\dfrac{-2}{5}+2\right)\)

\(=\dfrac{-3}{5}+\dfrac{-2}{5}+2\)

=-1+2

=1

c: \(8\dfrac{2}{7}-\left(3\dfrac{4}{9}+4\dfrac{2}{7}\right)\)

\(=8+\dfrac{2}{7}-3-\dfrac{4}{9}-4-\dfrac{2}{7}\)

\(=1-\dfrac{4}{9}=\dfrac{5}{9}\)