Cô ơi con sử dụng Canva để làm 1 thiệp tặng cô chủ nhiệm và tặng tất cả cô giáo trong Hoc24.vn ạ 

Quà này iem làm để tặng mẹ, chờ mẹ về iem sẽ tặng 

(Iem cx có quà cho mấy cô ó nhoa một lát rồi em sẽ đưa lên tại em cần phải sửa lại một số chỗ :3) 

1, I usually wear sport shoes

2, Yea of course I do, I have many different favourite kinds of shoes in my shoes collection :))

3, I often buy shoes depending on my mood :)

4, Shoes can be used as a cue to someone's personality or even his/her mood on that day. A study published in the Journal of Research in Personality in 2012 showed that 90 percent of people's personality is reflected in their choice of shoes. (my research on Google)

5, Uhm well, not actually, for me. Men may not interested in women's high heels, and women may not be interested in men's leather shoes. But by the way, they can both be interested in sport shoes or bisexual shoes. But who knows? Some of them may have the same attitude about shoes :)))

1. What kind of shoes do you usually wear?

=>  Yes, I often wear sneakers because it has a personality and fits with today's fashion

2. Do you have a favourite pair of shoes?

=> Yes, My favorite shoes are from Nike and it is specifically called "Nike jordan Dior high collar" and I can't buy it because the price of those shoes is very expensive.

3. How often do you buy shoes?

=> Yes, before the Covid-19 outbreak, I used to buy shoes at reputable shops and had many different types of shoes. But when Covid-19 was happening, I couldn't go to the shop but had to order online.

4. Do you think the type of shoes someone wears reflects their character?

=> In my opinion, it can also be said that it is true because everyone looks at appearance first. So you have to dress politely and trendy in that place and I think that goes well with shoes as well. If you go out on the street with a messy look, wearing a pair of ragged shoes, people will think you are different and vice versa. Therefore, we can say that shoes can tell someone's personality.

5. Do you think men and women have the same attitude towards shoes?

=> In my opinion, not because men often choose leather shoes to wear for durability and show luxury and nobility. Women often wear high heels or boots. But in middle age, there is a hobby of choosing the same sneakers to wear.

anh cho e hỏi tặng điểm là điểm j ạ?

Comment đầu 

\(u_k=u_{k-1}+4\left(k-1\right)+3=u_{k-2}+4\left(k-2\right)+4\left(k-1\right)+2.3=...\)

\(u_1+4\left(1+2+...+k-1\right)+3\left(k-1\right)=\left(2k+3\right)\left(k-1\right)\)

\(\Rightarrow lim\frac{\sqrt{u_{kn}}}{n}=lim\frac{\sqrt{\left(2km+3\right)\left(kn-1\right)}}{n}=k\sqrt{2}\)

Do đó :

\(\frac{a^{2019}+b}{c}=lim\frac{\sqrt{u_n}+\sqrt{u_{4n}}+\sqrt{u_{4^2n}}+...+\sqrt{u_{4^{2018}n}}}{\sqrt{u_n}+\sqrt{u_{2n}}+\sqrt{u_{2^2n}}+...+\sqrt{u_{2^{2018}n}}}\)

\(=lim\frac{\sqrt{2}\left(1+4+4^2+...+4^{2018}\right)}{\sqrt{2}\left(1+2+2^2+...+2^{2018}\right)}\)

\(=lim\frac{\frac{4^{2019}-1}{4-1}}{\frac{2^{2019}-1}{2-1}}=\frac{2^{2019}+1}{3}\)

\(\Rightarrow S=a+b-c=2+1-3=0\)

mình giải giúp bạn phần đầu phần sau bạn tự giải nha

From: ( your email ) 

To: (write your family's email )

Subject: Hello from Hanoi!

Hi,

My name is Pham Huy Duc. I'm 12 years old and I live in Ha Noi, in Vietnam. My mom's name is Nguyen Le, she is a maths teacher. My dad's name is Anh Tuan, he is an engineer. I have one younger sister. Her name is Lan Phuong. She's 10 years old.

FROM : NGUYEN PHUC LAM

TO   :NGO THI LAN HUONG

Subject: hello I'm from HOA BINH

 Hello

My name is Nguyen Phuc Lam.I'm 11 years old.I live in Hoa Binh province.My mom's name is Bui Thi Lieu,she is a worker.My dad's name is Nguyen The Hiep,he is a doctor and my younger brother nem is Nguyen Nhat Nam,he studing at Cuu Long primary school

I love my family very much.

Phải là: my younger brother's name is.... He studies ....

Đúng lúc em đg chuẩn bị thi luôn cô, ảo thật đấy

Với 1 chút kinh nghiệm thi nhiều năm, xin chia sẻ cho các bạn trong bài viết chiều nay, mong mọi người ủng hộ ạ :3

Ta có \(SA\perp\left(ABC\right)\Rightarrow SA\perp BC;SA\perp AB\) Mà \(BC\perp AB\Rightarrow BC\perp\left(SAB\right)\Rightarrow BC\perp SB\) => tg SAB là tg vuông tại B

Xét tg vuông SAB có

\(SB=\sqrt{SA^2+AB^2}=\sqrt{4a^2+a^2}=a\sqrt{5}\)

\(\Rightarrow S_{SBC}=\frac{SB.BC}{2}=\frac{a\sqrt{5}.a\sqrt{3}}{2}=\frac{a^2\sqrt{15}}{2}\)

Trong mp(SBC) dựng \(NK\perp SB\)(K thuộc SB) mà \(BC\perp SB\) => NK//BC

Ta có NS=NC

=> NK là đường trung bình của \(\Delta SBC\Rightarrow NK=\frac{BC}{2}=\frac{a\sqrt{3}}{2}\)

Ta có \(2SM=MB\Rightarrow SM=\frac{MB}{2}\Rightarrow SM=\frac{SB}{3}=\frac{a\sqrt{5}}{3}\)

\(\Rightarrow S_{SMN}=\frac{SM.NK}{2}=\frac{1}{2}.\frac{a\sqrt{5}}{3}.\frac{a\sqrt{3}}{2}=\frac{a^2\sqrt{15}}{12}\)

\(\Rightarrow S_{MNBC}=S_{SBC}-S_{SMN}=\frac{a^2\sqrt{15}}{2}-\frac{a^2\sqrt{15}}{12}=\frac{5a^2\sqrt{15}}{12}\)

Trong mp(SAB) từ A dựng đường thẳng \(AH\perp SB\) (H thuộc SB)

Ta có \(BC\perp\left(SAB\right)\Rightarrow BC\perp AH\)

\(\Rightarrow AH\perp\left(SBC\right)\) => AH là đường cao của hình chóp A.MNBC

Xét tg vuông SAB có

\(AB^2=BH.SB\Rightarrow BH=\frac{AB^2}{SB}=\frac{a^2}{a\sqrt{5}}=\frac{a\sqrt{5}}{5}\)

Xét tg vuông ABH có

\(AH=\sqrt{AB^2-BH^2}=\sqrt{a^2-\frac{5a^2}{25}}=\frac{2a\sqrt{5}}{5}\)

\(\Rightarrow S_{A.MNBC}=\frac{1}{3}.S_{MNBC}.AH=\frac{1}{3}.\frac{5a^2\sqrt{15}}{12}.\frac{2a\sqrt{5}}{5}=\frac{5a^3\sqrt{3}}{18}\)

nguyễn ngọc anh đúng

Chúc mừng chị San❄

Em xin cái comment đầu trước đã 

chúc mừng anh hưng phúc:)

Bạn giỏi quá chúc mừng bạn nha