Question

[Nguyễn Thị Hiền Nga]

Tính :

S = ( 1 - 1/1+2) . (1 - 1/1+2+3 ).....(1-1/1+2+3+...+2114)

Answer 1

[Trần Ngọc Bích Vân]

Ta có :

S = \(\dfrac{1-1}{1+2}.\dfrac{1-1}{1+2+3}.....\dfrac{1-1}{1+2+3+...+2114}\)

S = \(\dfrac{0}{1+2}.\dfrac{0}{1+2+3}....\dfrac{0}{1+2+3+...+2114}\)

S = 0.0....0

S = 0