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2-1.2n+4.2n=9.25
=>2n-1+22.2n=9.25
=>2n-1+2n+2=9.25
=>2n-1.(23+1)=9.25
=>2n-1.9=9.25
=>2n-1=25
=>n-1=5=>n=6
Ta có: \(2^{-1}\cdot2^n+4\cdot2^n=9\cdot2^5\)
\(\Leftrightarrow2^n\cdot2^{-1}+2^n\cdot2^2=9\cdot2^5\)
\(\Leftrightarrow2^n\cdot\left(2^{-1}+2^2\right)=9\cdot2^5\)
\(\Leftrightarrow2^n\cdot\dfrac{9}{2}=9\cdot2^5\)
\(\Leftrightarrow2^n=9\cdot2^5:\dfrac{9}{2}=2^5\cdot9\cdot\dfrac{2}{9}=2^6\)
hay n=6
Vậy: n=6
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a) \(\frac{1}{9}.27^n=3^n\)
\(=>\frac{27^n}{9}=3^n\)
\(=>3^n=3^n=>n=1\)
b) \(2^{-1}.2^n+4.2^n=9.2^5\)
\(=>2^{n-1}.2^2.2^n=9.2^5\)
\(=>2^{n-1}.2^{2+n}=9.2^5\)
\(=>2^{2n+1}=9.5^2\)
\(=>n=\)
Câu b đề sai hay sao ấy số xấu lắm
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c) 3n + 2 - 3n + 1 = 1458
=> 3n . 32 - 3n . 31 = 1458
=> 3n (32 - 3) = 1458
=> 3n . 6 = 1458
=> 3n = 243
=> n = 5
d) 2n - 1 + 4.2n = 9.25
=> 2n . 21 + 4.2n = 9.25
=> 2n (2 + 4) = 9.25
=> 2n . 6 = 9.25
=> 2n = \(\frac{9\cdot2^5}{6}=48\)
=> không tìm được x
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a, 9.27n=3n
32.33n=3n
32+3n=3n
2+3n=n
n-3n=2
-2n=2
n=-1
bạn nhớ k cho mk nha
b, (23:4).2n=4
(23:22).2n=22
21.2n=22
21+n = 22
1+n=2
n=1
bạn nhớ k cho minh nha
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\(\frac{1}{2}\cdot2^n+4.2^n=9.2^5\)
\(2^n\left(\frac{1}{2}+4\right)=9.32\)
\(2^n\left(\frac{1}{2}+\frac{8}{2}\right)=288\)
\(2^n\cdot\frac{9}{2}=288\)
\(2^n=288:\frac{9}{2}\)
\(2^n=288\cdot\frac{2}{9}\)
\(2^n=64\)
\(2^n=2^6\)
=> n = 6
vậy n = 6
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\Leftrightarrow2^n\left(\frac{1}{2}+4\right)=9\cdot2^5\Leftrightarrow2^n\cdot\frac{9}{2}=9\cdot2^5\Leftrightarrow2^n=2^6\Leftrightarrow n=6\)
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\(\dfrac{1}{2}\cdot2^n+4\cdot2^n=9\cdot2^5\\ \Rightarrow2^n\left(\dfrac{1}{2}+4\right)=9\cdot2^5\\ \Rightarrow2^n\cdot\dfrac{9}{2}=9\cdot2^5\\ \Rightarrow2^{n-1}\cdot9=9\cdot2^5\\ \Rightarrow n-1=5\\ \Rightarrow n=6\)
2n.(1/2+4)=9.32
2n*4,5=288
2n=64=26
=> n=6
\(2^{-1}.2^n+4.2^n=9.2^5\)
\(2^n.2=9.2^5\)
\(\Rightarrow2^n=9.2^4\)
Ko có n nhé bn