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2-1.2n+4.2n=9.25
=>2n-1+22.2n=9.25
=>2n-1+2n+2=9.25
=>2n-1.(23+1)=9.25
=>2n-1.9=9.25
=>2n-1=25
=>n-1=5=>n=6
Ta có: \(2^{-1}\cdot2^n+4\cdot2^n=9\cdot2^5\)
\(\Leftrightarrow2^n\cdot2^{-1}+2^n\cdot2^2=9\cdot2^5\)
\(\Leftrightarrow2^n\cdot\left(2^{-1}+2^2\right)=9\cdot2^5\)
\(\Leftrightarrow2^n\cdot\dfrac{9}{2}=9\cdot2^5\)
\(\Leftrightarrow2^n=9\cdot2^5:\dfrac{9}{2}=2^5\cdot9\cdot\dfrac{2}{9}=2^6\)
hay n=6
Vậy: n=6
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a, 9.27n=3n
32.33n=3n
32+3n=3n
2+3n=n
n-3n=2
-2n=2
n=-1
bạn nhớ k cho mk nha
b, (23:4).2n=4
(23:22).2n=22
21.2n=22
21+n = 22
1+n=2
n=1
bạn nhớ k cho minh nha
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\(2^{-1}.2^n+4.2^n=9.2^5\)
\(2^n.2=9.2^5\)
\(\Rightarrow2^n=9.2^4\)
Ko có n nhé bn
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a)\(\frac{1}{2}.2^n+4.2^n=9.2^5\)
\(\Leftrightarrow2^n\left(\frac{1}{2}+4\right)=9.32\)
\(\Leftrightarrow2^n.\frac{9}{2}=288\)
\(\Leftrightarrow2^n=288:\frac{9}{2}\)
\(\Leftrightarrow2^n=64\)
\(\Leftrightarrow2^n=2^6\) \(\Rightarrow n=6\left(TMBT\right)\)
Vậy: n=6
b) \(3^2.3^{-5}.3^n=3^{11}\)
\(\Leftrightarrow3^{2+\left(-5\right)+n}=3^{11}\)
\(\Leftrightarrow3^{\left(-3\right)+n}=3^{11}\)
\(\Rightarrow\left(-3\right)+n=11\)
\(\Leftrightarrow n=11-\left(-3\right)\) \(\Rightarrow n=11+3\Rightarrow n=14\)
Vậy n=14
c) Câu c này bạn làm giống như câu a) nha bởi vì nó cũng giống nhau thôi, bạn biến đổi \(2^{-1}=\frac{1}{2}\)rồi làm giống như trên câu a) nhé.
P/s: mình mới học lớp 6 lên 7. sai chỗ nào thông cảm cho mik với nhé. luôn nhá..
Cảm ơn ạ!!
![](https://rs.olm.vn/images/avt/0.png?1311)
a) \(9.27^n=3^5\Rightarrow3^2.\left(3^3\right)^n=3^5\)
\(\Rightarrow3^2.3^{3n}=3^5\Rightarrow3^{5n}=3^5\)
\(\Rightarrow5n=5\Rightarrow n=1\)
b)\(\left(2^3:4\right).2^n=4\Rightarrow\left(2^3:2^2\right).2^n=2^2\)
\(\Rightarrow2.2^n=2^2\Rightarrow2^{1+n}=2^2\)
\(\Rightarrow1+n=2\Rightarrow n=1\)
c)\(3^2.3^4.3^n=3^7\Rightarrow3^{6+n}=3^7\)
\(\Rightarrow6+n=7\Rightarrow n=1\)
d)\(2^{-1}.2^n+4.2^n=9.2^5\)
\(\Rightarrow2^n\left(2^{-1}+4\right)=3^2.2^5\)
\(\Rightarrow\)\(2^n\left(\frac{1}{2}+4\right)=3^2.2^5\)
\(\Rightarrow\)\(2^n.\frac{3^2}{2}=3^2.2^5\)
\(\Rightarrow\)\(2^{n-1}.3^2=3^2.2^5\)
\(\Rightarrow n-1=5\Rightarrow n=6\)
e)\(243\ge3^n\ge9.3^2\)
\(\Rightarrow3^5\ge3^n\ge3^2.3^2\)
\(\Rightarrow3^5\ge3^n\ge3^4\)
\(\Rightarrow5\ge n\ge4\Rightarrow5;4\)
f)\(2^{n+3}.2^n=128\)
\(\Rightarrow2^{n+3+n}=2^7\)
\(\Rightarrow2^{2n+3}=2^7\)
\(\Rightarrow2n+3=7\Rightarrow2n=4\Rightarrow n=2\)
Hok tối
![](https://rs.olm.vn/images/avt/0.png?1311)
a) \(\frac{1}{9}.27^n=3^n\)
\(\Leftrightarrow3^{-2}.3^{3n}=3^n\)
\(\Leftrightarrow3^{3n-2}=3^n\)
\(\Leftrightarrow3n-2=n\)
\(\Leftrightarrow2n=2\)
\(\Leftrightarrow n=1\)
b)\(3^{-2}.3^4.3^n=3^7\)
\(\Leftrightarrow3^{2+n}=3^7\)
\(\Leftrightarrow2+n=7\)
\(\Leftrightarrow n=5\)
![](https://rs.olm.vn/images/avt/0.png?1311)
c) 3n + 2 - 3n + 1 = 1458
=> 3n . 32 - 3n . 31 = 1458
=> 3n (32 - 3) = 1458
=> 3n . 6 = 1458
=> 3n = 243
=> n = 5
d) 2n - 1 + 4.2n = 9.25
=> 2n . 21 + 4.2n = 9.25
=> 2n (2 + 4) = 9.25
=> 2n . 6 = 9.25
=> 2n = \(\frac{9\cdot2^5}{6}=48\)
=> không tìm được x
![](https://rs.olm.vn/images/avt/0.png?1311)
a) \(\frac{1}{9}.27^n=3^n\)
\(=>\frac{27^n}{9}=3^n\)
\(=>3^n=3^n=>n=1\)
b) \(2^{-1}.2^n+4.2^n=9.2^5\)
\(=>2^{n-1}.2^2.2^n=9.2^5\)
\(=>2^{n-1}.2^{2+n}=9.2^5\)
\(=>2^{2n+1}=9.5^2\)
\(=>n=\)
Câu b đề sai hay sao ấy số xấu lắm