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a )\(\frac{a}{b}=\frac{c}{d}\Rightarrow\frac{a}{c}=\frac{b}{d}=\frac{a-b}{c-d}=\frac{2a}{2c}\)
\(\frac{a-b}{c-d}=\frac{2a}{2c}\Rightarrow\frac{a-b}{2a}=\frac{c-d}{2c}\) ( đpcm)
b ) \(\frac{a}{b}=\frac{c}{d}\Rightarrow\frac{a}{c}=\frac{b}{d}=\frac{5a}{5c}=\frac{3b}{3d}=\frac{3a}{3c}=\frac{2b}{2d}=\frac{5a-3b}{5c-3d}=\frac{3a+2b}{3c+2d}\)
\(\Rightarrow\frac{5a-3b}{3a+2b}=\frac{5c-3d}{3c+2d}\) ( đpcm )
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a) \(\hept{\begin{cases}\frac{a}{b}=\frac{c}{d}\Rightarrow\frac{a}{c}=\frac{b}{d}=\frac{5a}{5c}=\frac{3b}{3d}=\frac{5a-3b}{5c-3d}\\\frac{a}{c}=\frac{b}{d}\Rightarrow\frac{3a}{3c}=\frac{2b}{2d}=\frac{3a+2b}{3c+2d}\end{cases}}\)
\(\Rightarrow\frac{5a-3b}{5c-3d}=\frac{3a+2b}{3c+2d}\)
\(\Rightarrow\frac{5a-3b}{3a+2b}=\frac{5c-3d}{3c+2d}\)
b) Chứng minh tương tự
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\(\frac{a}{b}=\frac{c}{d}=>\frac{a}{c}=\frac{b}{d}\)
Áp dụng dãy tỉ số bằng nhau ta có:
\(\frac{a}{c}=\frac{b}{d}=\frac{5a}{5c}=\frac{3b}{3d}=\frac{5a-3b}{5c-3d}\)
\(\frac{a}{c}=\frac{b}{d}=\frac{3a}{3c}=\frac{2b}{2d}=\frac{3a+2b}{3c+2d}\)
=>\(\frac{5a-3b}{5c-3d}=\frac{a}{c}=\frac{3a+2b}{3c+3d}\)
=>\(\frac{5a-3b}{5c-3d}=\frac{3a+2b}{3c+3d}\)
=>\(\frac{5a-3b}{3a+2b}=\frac{5c-3d}{3c+3d}\)
\(\frac{a}{b}=\frac{c}{d}\Rightarrow\frac{a}{c}=\frac{b}{d}=\frac{5a}{5c}=\frac{3b}{3d}=\frac{5a-3b}{5c-3d}\)
\(\frac{a}{c}=\frac{b}{d}=\frac{3a}{3c}=\frac{2b}{2d}=\frac{3a+2b}{3c+2d}\)
=> \(\frac{5a-3b}{5c-3d}=\frac{3a+2b}{3c+2d}\) ( Vì cùng bằng \(\frac{a}{c}\))
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\(\dfrac{a}{b}\) = \(\dfrac{c}{d}\)
\(\dfrac{a}{c}\) = \(\dfrac{b}{d}\)
\(\dfrac{a}{c}\) = \(\dfrac{5a}{5c}\) = \(\dfrac{3b}{3d}\) Áp dụng tính chất dãy tỉ số bằng nhau ta có:
\(\dfrac{a}{c}\) = \(\dfrac{5a+3b}{5c+3d}\) (1)
\(\dfrac{a}{c}\) = \(\dfrac{5a-3b}{5c-3d}\) (2)
Kết hợp (1) và (2) ta có:
\(\dfrac{5a+3b}{5c+3d}\) = \(\dfrac{5a-3b}{5c-3d}\)
⇒ \(\dfrac{5a+3b}{5a-3b}\) = \(\dfrac{5c+3d}{5c-3d}\) (đpcm)
b; \(\dfrac{a}{b}\) = \(\dfrac{c}{d}\)
\(\dfrac{a}{b}\) = \(\dfrac{3a}{3b}\) = \(\dfrac{2c}{2d}\)
Áp dụng tính chất dãy tỉ số bằng nhau ta có:
\(\dfrac{a}{b}\) = \(\dfrac{3a+2c}{3b+2d}\) (đpcm)
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a.a/b=c/d=>.a/c=b/d=>2a/2c=b/d
ap dung tính chất dãy tỉ sồ bàng nhau ya có
2a/2c=b/d=2a+b/2c+d=2a-b/2c-d
=>2a+b/2a-b=2c+d/2c-d
b.a/b=c/d=>a/c=b/d=>5a/5c=3b/3d=3a/3c=2b/2d
áp dụng tính chat dãy ti số bang nhau ta co
5a/5c=3b/3d=3a/3c=2b/2d=5a-3b/5c-3d=3a+2b/3c+2d
5a-3b/3a+2b=5c-3d/3c+2d
bạn bấm vào đây cho mình nhé !CMR:từ tỉ lệ thức $\frac{a}{b}=\frac{c}{d}$ab =cd ta suy ra được $\frac{5a-3b}{3a+2b}=\frac{5c-3d}{3c+2d}$5a−3b3a+2b =5c−3d3c+2d