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\(\left(3x-1\right)⋮\left(x+2\right)\Leftrightarrow\left[3\left(x+2\right)-7\right]⋮\left(x+2\right)\Leftrightarrow7⋮\left(x+2\right)\)
\(\Leftrightarrow\left(x+2\right)\inƯ\left(7\right)=\left\{-7,-1,1,7\right\}\Leftrightarrow x\in\left\{-9,-3,-1,5\right\}\).
![](https://rs.olm.vn/images/avt/0.png?1311)
\(12.7+4.21+2.42+6.14+84\)
\(=12.7+4.3.7+2.6.7+6.2.7+12.7\)
\(=5.12.7\)
\(=60.7+420\)
![](https://rs.olm.vn/images/avt/0.png?1311)
gọi d là (25n+7;15n+4)
\(\Rightarrow\hept{\begin{cases}25n+7⋮d\\15n+4⋮d\end{cases}\Rightarrow\hept{\begin{cases}3\left(25n+7\right)⋮d\\5\left(15n+4\right)⋮d\end{cases}}\Rightarrow\hept{\begin{cases}75n+21⋮d\\75n+10⋮d\end{cases}}}\)
=> 75n+21-(75n+20) \(⋮\) d
=> 1\(⋮\)d
=> d= 1
vậy ƯCLN của 15n+7 và 15n+4 là 1
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\left(-2\right).9=3.\left(-6\right)\)
\(\Rightarrow\frac{-2}{3}=\frac{-6}{9};\frac{-2}{-6}=\frac{3}{9};\frac{3}{-2}=\frac{9}{-6};\frac{9}{3}=\frac{-6}{-2}\)
#H
(Thiếu thì bổ sung nhá)
??????????????????
I don't understand.