b, đề phải là A = 3^450 chứ bạn ơi

Có : A = 3^450 = (3^3)^150 = 27^150

B = 5^300 = (5^2)^150 = 25^150

Vì 27^150 > 25^150 => 3^450 > 5^300

Tk mk nha

a, Có : 2A = 2+2^2+.....+2^10

A = 2A-A = (2+2^2+.....+2^10)-(1+2+2^2+.....+2^9) = 2^10-1

=> A < B

Jmgoxpig och ogu o chxjf yvb

8vuob 

\(\frac{3\cdot4+3\cdot7}{6\cdot5+9}\)

\(=\frac{3\cdot\left(4+7\right)}{3\cdot3\cdot5+3\cdot3}\)

\(=\frac{3\cdot11}{3\cdot\left(3\cdot5+3\right)}\)

\(=\frac{3\cdot11}{3\cdot11}\)

\(=1\)

bn ơi 6= 2.3 mak

\(2\left(5-x\right)+5=1-3x\)

\(10-2x+5=1-3x\)

\(-2x+3x=1-10-5\)

\(x=-14\)

Ta có: \(2\left(5-x\right)+5=1-3x\Leftrightarrow10-2x+5=1-3x\Leftrightarrow15=1-x\Leftrightarrow x=-14\)

Vậy \(x=-14\)

Nhờ cậu tk cho tớ nhé  ! Thank you 

(5-x) + 5 = 1-3x

=> 5 - x + 5 = 1 - 3x

=> (5+5) - x = 1 - 3x

=> 10 - x = 1 - 3x

=> -x + 3x = 1 - 10

=> 2x = 9

=> x = \(\frac{9}{2}\)

2 nhân mở ngoặc 5-x đóng ngoặc cộng 5 bằng 1-3x

\(\frac{-3}{8}=\frac{-3\cdot3}{8\cdot3}=\frac{-9}{24}\)

\(\frac{2}{-3}=\frac{2\cdot\left(-8\right)}{-3\cdot\left(-8\right)}=\frac{-16}{24}\)

\(\frac{-3}{-4}=\frac{-3\cdot\left(-6\right)}{-4\cdot\left(-6\right)}=\frac{18}{24}\)

\(\frac{3}{-72}=\frac{3\div\left(-3\right)}{-72\div\left(-3\right)}=\frac{-1}{24}\)

\(\frac{5}{-6}=\frac{5\cdot\left(-4\right)}{-6\cdot\left(-4\right)}=\frac{-20}{24}\)

\(\frac{-3}{8}=\frac{-9}{24};\frac{2}{-3}=\frac{-2}{3}=\frac{-16}{24};\frac{-3}{-4}=\frac{3}{4}=\frac{18}{24};\frac{3}{-72}=\frac{-1}{24};\frac{5}{-6}=\frac{-5}{6}=\frac{-20}{24}\)