999.999.999.999.999.999 999 999999999999999999×999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999
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![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
12*4 = 48
a:1 = a* 1
Suy ra a*1 - A:1 =0
Kết quả biểu thức là 48
![](https://rs.olm.vn/images/avt/0.png?1311)
Số đường có trong nc ngọt là: 4,05:100x50=0,2025 kg=202,5 g
Khi đổ như vậy số đường trong nc ngọt là: 4,05:100x4,5=0,18225 kg=182,25 g
Vậy cần đổ số g nc vào nc ngọt là: 202,5-182,25=20,25 g
Đ/S :20,25 g nc
![](https://rs.olm.vn/images/avt/0.png?1311)
Gọi độ dài các cạnh MN, NP, MP lần lượt là \(a,b,c\left(cm\right);a,b,c>0\).
Vì độ dài các cạnh MN, NP, MP lần lượt tỉ lệ với \(3,4,5\)nên \(\frac{a}{3}=\frac{b}{4}=\frac{c}{5}\).
Vì chu vi tam giác MNP là \(60cm\)nên \(a+b+c=60\)
Áp dụng tính chất dãy tỉ số bằng nhau ta có:
\(\frac{a}{3}=\frac{b}{4}=\frac{c}{5}=\frac{a+b+c}{3+4+5}=\frac{60}{12}=5\)
\(\Leftrightarrow\hept{\begin{cases}a=5.3=15\\b=5.4=20\\c=5.5=25\end{cases}}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(183+80\div[20-4\left(5^2-24\right)]\)
\(=183+80\div[20-4\left(25-24\right)]\)
\(=183+80\div[20-4.1]\)
\(=183+80\div[20-4]\)
\(=183+80\div16\)
\(=183+5\)
\(=188\)
![](https://rs.olm.vn/images/avt/0.png?1311)
Vì ( 2x - 4).( 3x + 9 ) = 0
=> 2x - 4 hoặc 3x + 9 = 0
TH1: 2x - 4 = 0
2x = 4
x=2
TH2: 3x + 9 = 0
3x = -9
x = -3
Vậy, x = -3 hoặc 2
\(\left(2x-4\right)\left(3x+9\right)=0\)
\(\orbr{\begin{cases}2x-4=0\\3x+9=0\end{cases}}\)
TH1. \(2x-4=0\)
\(2x=4\)
\(x=2\)
TH2. \(3x+9=0\)
\(3x=9\)
\(x=3\)
Vậy \(x\in\left\{2;3\right\}\)
@Nghệ Mạt
#cua
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