tìm x
\(\left(\frac{4}{3}\right)^x=\frac{2^8}{3^4}\)
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N =\(\frac{2010+2011+2012}{2011+2012+2013}\)
\(\Rightarrow N=\frac{2010}{2011+2012+2013}+\frac{2011}{2011+2012+2013}+\frac{2012}{2011+2012+2013}\)
Do: \(\frac{2010}{2011}>\frac{2010}{2011+2012+2013};\frac{2011}{2012}>\frac{2011}{2011+2012+2013};\frac{2012}{2013}>\frac{2012}{2011+2012+2013}\)
\(\Rightarrow\frac{2010}{2011}+\frac{2011}{2012}+\frac{2012}{2013}>\frac{2010}{2011+2012+2013}+\frac{2011}{2011+2012+2013}+\frac{2012}{2011+2012+2013}\)
\(\Rightarrow\frac{2010}{2011}+\frac{2011}{2012}+\frac{2012}{2013}>\frac{2010+2011+2012}{2011+2012+2013}\Leftrightarrow N>M\)
\(\left(\frac{4}{3}\right)^x=\frac{\left(2^2\right)^4}{3^4}=\frac{4^4}{3^4}=\left(\frac{4}{3}\right)^4\Rightarrow x=4\)
\(\left(\frac{4}{3}\right)^x=\frac{\left(2^2\right)^4}{3^4}\)
\(=\frac{4^4}{3^4}\)
\(=\left(\frac{4}{3}\right)^4\)
\(\Leftrightarrow x=4\)
nha bn