cho A = 4 + 42 + 43 + .... + 423 + 424 . chứng minh A ⋮ 20 , A⋮21 , A⋮420
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CM: A ⋮ 5
A = 1 + 4 + 42 + 43 + ... + 460
A = (1 + 4) + (42 + 43) + ... + (459 + 460)
A = 5 + 42 . (1 + 4) + ... + 459 . (1 + 4)
A = 5 + 42 . 5 + ... + 459 . 5
A = 5 . (1 + 42 + ... + 459) ⋮ 5
Vậy A ⋮ 5
CM: A ⋮ 21
A = 1 + 4 + 42 + 43 + ... + 460
A = (1 + 4 + 42) + (43 + 44 + 45) + ... + (458 + 459 + 460)
A = 21 + 43 . (1 + 4 + 42) + ... + 458 . (1 + 4 + 42)
A = 21 + 43 . 21 + ... + 458 . 21
A = 21 . (1 + 43 + ... + 458) ⋮ 21
Vậy A ⋮ 21
![](https://rs.olm.vn/images/avt/0.png?1311)
\(A=2+2^2+2^3+\dots+2^{60}\\=(2+2^2)+(2^3+2^4)+(2^5+2^6)+\dots+(2^{59}+2^{60})\\=6+2^2\cdot(2+2^2)+2^4\cdot(2+2^2)+\dots+2^{58}\cdot(2+2^2)\\=6+2^2\cdot6+2^4\cdot6+\dots+2^{58}\cdot6\\=6\cdot(1+2^2+2^4+\dots+2^{58})\)
Vì \(6\cdot(1+2^2+2^4+\dots+2^{58})\vdots6\)
nên \(A\vdots6\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(12x-144=0\)
\(\Rightarrow12x=144\)
\(\Rightarrow x=144:12\)
\(\Rightarrow x=12\)
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-54.76 + 46.(-76)
= 54.(-76) + 46.(-76)
= (-76).(54 + 46)
= -76. 100
= -7600
Lời giải:
$-54\times 76+46\times (-76)=54\times (-76)+46\times (-76)$
$=(-76)\times (54+46)=(-76)\times 100=-7600$
![](https://rs.olm.vn/images/avt/0.png?1311)
Lời giải:
$25-(x+11)=x-16$
$25=x-16+x+11=2x-5$
$2x=25+5=30$
$x=30:2=15$
![](https://rs.olm.vn/images/avt/0.png?1311)
a, 32.(-64) - 64.68
= -64( 32 + 68)
= -64 .100
= - 6400
b, -54.76 + 46.(-76)
= -76.(54 + 46)
= - 76. 100
= - 7600
c, 75.18 + 18.25
= 18.(75 + 25)
= 18 . 100
= 1800
d, (-4).(3).(-125)(-25).(-8)
= 3.(-4. (-25).((-125).(-8)
= 3.100.1000
= 300000
![](https://rs.olm.vn/images/avt/0.png?1311)
Lời giải:
$A=(4+4^2)+(4^3+4^4)+...+(4^{23}+4^{24})$
$=(4+4^2)+4^2(4+4^2)+...+4^{22}(4+4^2)$
$=(4+4^2)(1+4^2+....+4^{22})=20(1+4^2+...+4^{22})\vdots 20$
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$A=(4+4^2+4^3)+(4^4+4^5+4^6)+....+(4^{22}+4^{23}+4^{24})$
$=4(1+4+4^2)+4^4(1+4+4^2)+....+4^{22}(1+4+4^2)$
$=(1+4+4^2)(4+4^4+....+4^{22})=21(4+4^4+...+4^{22})\vdots 21$
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Vậy $A\vdots 20; A\vdots 21$. Mà $(20,21)=1$ nên $A\vdots (20.21)$ hay $A\vdots 420$