a) = x⁵+x⁴+x³+x²+x+1-x³-x²-x=

x³(x²+x+1)+(x²+x+1) - x(x²+x+1)

bn nhóm vào là xong,mà bn hỏi ít thôi, hỏi nhiều ai làm cho nổi

1³ = (\(x+y\))³ = \(x^3\) + 3\(x^2\)y + 3\(xy^2\) + y³ = \(x^3\)+y³+3\(xy\)(\(x+y\))

1 = \(x^3\)+y³+3\(xy\)

1³ = (\(x-y\))³ = \(x^3\) - 3\(x^2\)y + 3\(xy\) - y³ = \(x^3\) - y³ - 3\(xy\)(\(x-y\))

1 = \(x^3\) - y³ - 3\(xy\)

b) ( x+ 2) ( 3x-2) - (3x-1) ( x-5) = 11

3x^2 +6x - 2x -4 - 3x^2 +x + 15x -5 =11

20x = 11 +4+5

20x = 20

x=1

c) 2(2x+ 1) ( 8x-3) + ( 3-4x) ( 8x-7) = 6x + 73

(4x + 2)(8x-3) + 24x - 32x^2 -3 +4x = 6x +73

32x^2 + 16x - 12x  + 24x - 32x^2 +4x -6x = 73 +6 +3

26x = 82

x= 41/13

a. \(\left(x+2\right)\left(3x-2\right)-\left(3x-1\right)\left(x-5\right)=11\)

\(\Rightarrow3x^2-2x+6x-4-3x^2+15x+x-5=11\)

\(\Rightarrow20x-9=11\)

\(\Rightarrow x=1\)

Vậy..................

b. \(2\left(2x+1\right)\left(8x-3\right)+\left(3-4x\right)\left(8x-7\right)=6x+73\)

\(\Rightarrow\left(4x+2\right)\left(8x-3\right)+\left(3-4x\right)\left(8x-7\right)=6x+73\)

\(\Rightarrow32x^2-12x+16x-6+24x-21-32x^2+28x-6x=73\)

\(\Rightarrow50x-27=73\)

\(\Rightarrow x=100\)

Vậy..............