a.500-{5[409-(23.3-21)2]+103}÷15
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A={-6;-5;-4;-3;-2;-1;0;1;2}
B={72;144;216;288;360;432}
NHỚ "K" CHO MÌNH VỚI ĐÓ !!! :33
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Ta có : \(\frac{3^{10}.11+3^{10}.5}{3^9.2^4}=\frac{3^{10}.\left(11+5\right)}{3^9.16}=\frac{3^{10}.16}{3^9.16}=3\)3
\(\frac{3^{10}.11+3^{10}.5}{3^9.2^4}=\frac{3^{10}.\left(11+5\right)}{3^9.2^4}\) \(=\frac{3^{10}.16}{3^9.2^4}=\frac{3^{10}.2^4}{3^9.2^4}=3\)
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Ta có : 2+22+23+...+260
=(2+22+23+24)+(25+26+27+28)+...+(257+258+259+260)
=2(1+2+22+23)+25(1+2+22+230+...+257(1+2+22+23)
=2.15+25.15+...+257.15\(⋮\)15
hay 2+22+23+..+260\(⋮\)15
Vậy 2+22+23+...+260\(⋮\)15.
Đặt:
M=21+22+23+...+260
M=(21+22+23+24)+(25+26+27+28)+...+(257+258+259+260)
M=2(1+2+22+23)+25(1+2+22+23)+...+257(1+2+22+23)
M=2.15+25.15+257.15
M=15(2+25+...+257)
=>M chia hết cho 15
Vậy M chia hết cho 15(đpcm)
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= 188 - ( 4 . 25 - 3 . 8 + 8 : 2 )
= 188 - ( 100 - 24 + 4 )
= 188 - 80
= 108
188 - ( 4. 52 - 3. 23 + 23 : 2)
= 188 - ( 100 - 24 + 4)
= 188 - 80
= 108
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Ta có:
2n+10=2n+4+6=2(n+2)+6
Vì 2(n+2)+6\(⋮\)n+2
mà 2(n+2)\(⋮\)n+2
\(\Rightarrow\)6\(⋮\)n+2
\(\Rightarrow\)n+2\(\inƯ\left(6\right)=\left\{-6;-3;-2;-1;1;2;3;6\right\}\)
\(\Rightarrow\)n\(\in\left\{-8;-5;-4;-3;-1;0;1;4\right\}\)
mà n là số lớn nhất
\(\Rightarrow\)n=4
Vậy n=4
\(500-\left\{5\left[409-\left(2^3^{ }.3-21\right)^2\right]+10^3\right\}:15\)\(5\)
\(=500-\left\{5\left[409-\left(8.3-21\right)^2\right]+1000\right\}:15\)
\(=500-\left\{5\left[409-\left(24-21\right)^2\right]+1000\right\}:15\)