tìm x
460 + 85 x 4 = ( x + 200) x 4
(x-7)(2x-8)=0
x -280 : 35=5x54
324 + 16x(2x+3)=404
K
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23 tháng 2 2023
a: =>31-x=60
=>x=-29
b: =>(x-140):35=280-270=10
=>x-140=350
=>x=490
c: =>(1900-2x):35=48
=>1900-2x=1680
=>2x=220
=>x=110
d: =>\(2^{2x-1}=2^9\cdot2=2^{11}\)
=>2x-1=11
=>x=6
e: =>(x+2)^5=4^5
=>x+2=4
=>x=2
f: =>3x-4=0 hoặc x-1=0
=>x=4/3 hoặc x=1
g: =>(2x-1)^2=49
=>2x-1=7 hoặc 2x-1=-7
=>x=-3 hoặc x=4
h: =>x(x+1)/2=78
=>x(x+1)=156
=>x=12
7 tháng 7 2016
1)\(\left(x-280\right):35=56.5\)
\(\left(x-280\right):35=280\)
\(x-280=280.35\)
\(x-280=9800\)
\(x=9800+280\)
\(x=10080\)
2) \(\left(x-128+20\right):192=0\)
\(\Rightarrow\left(x-148\right):192=0\)
\(\Rightarrow x-148=0\)
\(\Rightarrow x=0+148\)
\(\Rightarrow x=148\)
3) \(460+85.4=\left(x+200\right).4\)
\(\Rightarrow\left(x+200\right).4=460+340\)
\(\Rightarrow\left(x+200\right).4=800\)
\(\Rightarrow x+200=800:4=200\)
\(\Rightarrow x+200=200\)
\(\Rightarrow x=200-200=0\)
4) \(x+5.2-\left(32+16.3:16-15\right)=0\)
\(\Rightarrow x+10-\left(32+3-15\right)=0\)
\(\Rightarrow x+10-20=0\)
\(\Rightarrow x+10=20\)
\(\Rightarrow x=20-10=10\)
nha m.n
10 tháng 10 2021
\(a,\Rightarrow x+35=103\\ \Rightarrow x=68\\ b,\Rightarrow x+7=42\\ \Rightarrow x=35\\ c,\Rightarrow x-15=9\\ \Rightarrow x=24\\ d,\Rightarrow x+23=31\\ \Rightarrow x=8\\ e,\Rightarrow18-x=6\\ \Rightarrow x=12\\ f,\Rightarrow x+14=34\\ \Rightarrow x=20\\ g,\Rightarrow2x+1=21\\ \Rightarrow x=11\\ h,\Rightarrow3\left(x+1\right)=99\\ \Rightarrow x+1=33\Rightarrow x=32\\ i,5\left(x-3\right)=25\\ \Rightarrow x-3=5\\ \Rightarrow x=8\\ j,\Rightarrow8\left(2x+7\right)=88\\ \Rightarrow2x+7=11\Rightarrow x=2\\ k,\Rightarrow5\left(x+4\right)=85\\ \Rightarrow x+4=17\\ \Rightarrow x=13\)
24 tháng 9 2021
1) \(ĐK:x\in R\)
2) \(ĐK:x< 0\)
3) \(ĐK:x\in\varnothing\)
4) \(=\sqrt{\left(x+1\right)^2+2}\)
\(ĐK:x\in R\)
5) \(=\sqrt{-\left(a-4\right)^2}\)
\(ĐK:x\in\varnothing\)
NT
Nguyễn Thị Thương Hoài
Giáo viên
VIP
14 tháng 6
a; - \(\dfrac{1}{3}\).(15\(x-9\)) + \(\dfrac{2}{7}\).(- \(x-34\)) = 1 - \(\dfrac{3}{4}\).(-16\(x+4\))
- 5\(x\) + 3 - \(\dfrac{2}{7}\)\(x\) - \(\dfrac{68}{7}\) = 1 + 12\(x\) - 3
12\(x\) + 5\(x\) + \(\dfrac{2}{7}x\) = 3 - \(\dfrac{68}{7}\) - 1 + 3
17\(x\) + \(\dfrac{2}{7}x\) = (3 - 1 + 3) - \(\dfrac{68}{7}\)
\(\dfrac{121}{7}\)\(x\) = 5 - \(\dfrac{68}{7}\)
\(\dfrac{121}{7}\) \(x\) = - \(\dfrac{33}{7}\)
\(x\) = - \(\dfrac{33}{7}\): \(\dfrac{121}{7}\)
\(x\) = - \(\dfrac{3}{11}\)
Vậy \(x\) = - \(\dfrac{3}{11}\)
NA
1
SN
20 tháng 7 2021
a. 2x+\(\dfrac{4}{5}\)=0 hoặc 3x-\(\dfrac{1}{2}\)=0
2x=- 4/5 hoặc 3x=1/2
x=-2/5 hoặc x=\(\dfrac{1}{6}\)
b. x-\(\dfrac{2}{5}\)=0 hoặc x+\(\dfrac{4}{7}\)=0
x=2/5 hoặc x=-\(\dfrac{4}{7}\)
d. x(1+5/8-12/16)=1
\(\dfrac{7}{8}\)x=1=> x=8/7
\(460+85\times4=\left(x+200\right)\times4\)
\(\left(x+200\right)\times4=460+340\)
\(\left(x+200\right)\times4=800\)
\(x+200=800:4\)
\(x+200=200\)
\(x=200-200\)
\(x=0\)
~~~
\(\left(x-7\right)\left(2x-8\right)=0\)
\(+, TH1: x - 7 = 0\)
\(x=0+7\)
\(x=7\)
\(+, TH2 : 2x - 8 = 0 \)
\(2x=0+8\)
\(2x=8\)
\(x=8:2\)
\(x=4\)
~~~
\(x-280:35=5\times54\)
\(x-8=270\)
\(x=270+8\)
\(x=278\)
~~~
\(324+16\times\left(2x+3\right)=404\)
\(16\times\left(2x+3\right)=404-324\)
\(16\times\left(2x+3\right)=80\)
\(2x+3=80:16\)
\(2x+3=5\)
\(2x=5-3\)
\(2x=2\)
\(x=2:2\)
\(x=1\)
#\(Toru\)
`460 + 85 xx 4 = ( x + 200) xx 4`
`460 + 340 = (x+200)xx4`
` 800= (x+200)xx4`
`x+200=800:4`
`x+200=200`
`x=200-200`
`x=0`
__
`(x-7)(2x-8)=0`
`@ TH1`
`x-7=0`
`x=0+7`
`x=7`
`@ TH2`
`2x-8=0`
`2x=0+8`
`2x=8`
`x=8:2`
`x=4`
__
`x -280 : 35=5xx54`
`x -280 : 35=270`
`x-8=270`
`x=270+8`
`x=278`
__
`324 + 16xx(2x+3)=404`
`16xx(2x+3)=404 -324`
`16xx(2x+3)=80`
`2x+3=80:16`
`2x+3=5`
`2x=5-3`
`2x=2`
`x=2:2`
`x=1`