12:2+12x2=?
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![](https://rs.olm.vn/images/avt/0.png?1311)
\(12\times4+12\times2+12+12\)
\(=12\times4+12\times2+12\times1+12\times1\)
\(=12\times\left(4+2+1+1\right)\)
\(=12\times8\)
\(=96\)
![](https://rs.olm.vn/images/avt/0.png?1311)
5/12 x 2/3 + 2/3 x 7/12 + 1/3
= 2/3 x ( 5/12 + 7/12 ) + 1/3
= 2/3 x 1 + 1/3
= 2/3 + 1/3
= 1
5/12x2/3+2/3x7/12+1/3
=2/3x(5/12+7/12)+1/3
=2/3x1+1/3
=2/3+1/3
=1
k tui nha @@@
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\(a,=1,6^2+2\cdot1,6\cdot3,4+3,4^2=\left(1,6+3,4\right)^2=5^2=25\\ b,Sửa:x^4-12x^3+12x^2-12x+11\\ =x^4-11x^3-x^3+11x^2+x^2-11x-x+11=x^3\left(x-11\right)-x^2\left(x-11\right)+x\left(x-11\right)-\left(x-11\right)\\ =\left(x-11\right)\left(x^3-x^2+x-1\right)=\left(x-11\right)\left(x-1\right)\left(x^2+1\right)\\ c,=\left(x^2+3\right)^2-\left(x^2-4\right)\left(x^2+12\right)\\ =x^4+6x^2+9-x^4-8x^2+48=-2x^2+57\)
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\(\dfrac{-5}{12}\times\dfrac{2}{11}+\dfrac{-5}{11}\times\dfrac{9}{11}+\dfrac{5}{12}\\ =\dfrac{5}{12}\times\left(1-\dfrac{2}{11}\right)+\dfrac{-5}{11}\times\dfrac{9}{11}\\ =\dfrac{5}{12}\times\dfrac{9}{11}+\dfrac{-5}{11}\times\dfrac{9}{11}\\ =\dfrac{9}{11}\times\left(\dfrac{5}{12}-\dfrac{5}{11}\right)\\ =\dfrac{9}{11}\times\dfrac{-5}{132}=-\dfrac{15}{484}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
A = \(\dfrac{-5}{12}\)x\(\dfrac{2}{11}\)+\(\dfrac{-5}{12}\)x\(\dfrac{9}{11}\)+\(\dfrac{5}{12}\)
A= \(\dfrac{-5}{12}\)(\(\dfrac{2}{11}\)+\(\dfrac{9}{11}\)-1)
A = 0
30
= 30