Thực hiện phép tính sau ( tính hợp lý nếu có thể ) :
( 23.94 + 93.45) : ( 92.10 - 92 )
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Bài 3:
a: Ta có: 60-3(x-2)=51
\(\Leftrightarrow x-2=3\)
hay x=5
b: Ta có: \(4x-20=25:2^2\)
\(\Leftrightarrow4x=\dfrac{25}{4}+20=\dfrac{105}{4}\)
hay \(x=\dfrac{105}{16}\)
c: Ta có: \(8\cdot6+288:\left(x-3\right)^2=50\)
\(\Leftrightarrow288:\left(x-3\right)^2=50-48=2\)
\(\Leftrightarrow\left(x-3\right)^2=144\)
\(\Leftrightarrow\left[{}\begin{matrix}x-3=12\\x-3=-12\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=15\\x=-9\end{matrix}\right.\)
a) (-124) + 24 = -100
b) 37. 78 + 37. 22
= 37 . ( 78 + 22 )
= 37 . 100
= 3700
\(\left(2^3\cdot9^4+9^3+45\right):\left(9^2\cdot10-9^2\right)\)
\(=\dfrac{9^3\cdot\left(2^3\cdot9+1\right)+45}{9^3}\)
\(=\dfrac{9^3\cdot73+45}{9^3}=\dfrac{5918}{81}\)
\(3^{^{ }2}\) . 5 + 23.10 - 81: 3
= 9.5 + 8.10 - 27
= 45 + 80 - 27
= 125 - 27
= 98
\(3^2\cdot5+2^3\cdot10-81:3\)
\(=9\cdot5+8\cdot10-3^4:3\)
\(=40+80-3^3\)
\(=120-27\)
\(=93\)
\(A=-\dfrac{1}{6}-\left[\dfrac{9}{16}-\dfrac{9}{8}+\dfrac{3}{4}\right]\)
\(=\dfrac{-1}{6}-\dfrac{9-18+12}{16}=\dfrac{-1}{6}-\dfrac{3}{16}\)
\(=\dfrac{-8}{48}-\dfrac{9}{48}=-\dfrac{17}{48}\)
\(B=\left(-\dfrac{3}{4}+\dfrac{3}{4}\right)^2+\dfrac{3}{4}\cdot\dfrac{-5}{9}+7^3\)
=-15/36+343
=343-5/12=4111/12
\(=64\cdot\dfrac{-1}{8}+100\cdot\dfrac{1}{100}\)
=-8+1
=-7
e: =5/7(5/11+2/11-14/11)
=5/7(-7/11)=-5/11
f: =-5/4(2/11+9/11)+1+3/4
=-5/4+7/4
=2/4=1/2
g: =-5/7(3/13+10/13)+1+5/7
=-5/7+1+5/7
=1
h: =7/4(29/5-9/5)+41/13
=-7+41/13=-50/13
\(\dfrac{\dfrac{5}{3}-\dfrac{5}{7}+\dfrac{5}{9}}{\dfrac{10}{3}-\dfrac{10}{7}+\dfrac{10}{9}}=\dfrac{5\left(\dfrac{1}{3}-\dfrac{1}{7}+\dfrac{1}{9}\right)}{10\left(\dfrac{1}{3}-\dfrac{1}{7}+\dfrac{1}{9}\right)}=\dfrac{1}{2}\)
(23.94+93.45):(92.10-92)
= ( 8. 94+93.9.5):(81.10-81)
= (8.94+94.5):(810-81)
=[94.(8+5)]:729
=[94.13]:729
=6561.13:729
=6561:729.13
=9.13
=117
Mk nhanh nhat day![ok ok](/media/olmeditor/plugins/smiley/images/ok.png)
(23.94+93.45):(92.10-92)
=(23.94+5.94):(81.10-81)
=[94.(8+5)]:(810-81)
=(6561.13):729
=85296:729
=117