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4/9 x 3/8 + 5/8 = 1/6 + 5/8 = 19/24
1/3 : 1/6 - 5/11 = 2 - 5/11 = 17/11
1/6 : 1/4 x 9/8 = 2/3 x 9/8 = 3/4
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a: \(=\dfrac{3}{5}\cdot\dfrac{5}{4}+\dfrac{1}{2}\cdot\dfrac{2}{3}=\dfrac{3}{4}+\dfrac{1}{3}=\dfrac{9+4}{12}=\dfrac{13}{12}\)
b: \(\Leftrightarrow x\cdot\dfrac{5}{4}=\dfrac{5}{8}\)
hay x=1/2
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\(=\dfrac{3}{5}+\dfrac{8}{15}:\dfrac{2}{7}=\dfrac{3}{5}+\dfrac{28}{15}=\dfrac{9}{15}+\dfrac{28}{15}=\dfrac{37}{15}\)
\(=\dfrac{7}{8}+\dfrac{7}{3}-\dfrac{11}{12}=\dfrac{77}{24}-\dfrac{11}{12}=\dfrac{55}{24}\)
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Lời giải:
a.
$\frac{5}{15}-\frac{1}{6}\times \frac{2}{5}=\frac{5}{15}-\frac{1}{15}=\frac{4}{15}$
b.
$\frac{8}{24}+\frac{3}{4}:\frac{1}{8}=\frac{1}{3}+6=\frac{19}{3}$
c.
$\frac{1}{7}: \frac{2}{8}-\frac{1}{7}=\frac{1}{7}\times 4-\frac{1}{7}$
$=\frac{1}{7}\times (4-1)=\frac{1}{7}\times 3=\frac{3}{7}$
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\(\dfrac{11}{2}\): \(\dfrac{1}{4}\) \(\times\) \(\dfrac{5}{3}\)
= \(\dfrac{11}{2}\) \(\times\) \(\dfrac{4}{1}\) \(\times\) \(\dfrac{5}{3}\)
= 22 \(\times\) \(\dfrac{5}{3}\)
= \(\dfrac{110}{3}\)
\(\dfrac{5}{2}-\dfrac{1}{4}+\dfrac{5}{3}\)
= \(\dfrac{30}{12}-\dfrac{3}{12}+\dfrac{20}{12}\)
= \(\dfrac{7}{12}\)
\(\dfrac{14}{5}\times\dfrac{2}{3}\)+ 5
= \(\dfrac{28}{15}\) + 5
= \(\dfrac{28}{15}\) + \(\dfrac{75}{15}\)
= \(\dfrac{103}{15}\)
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Bài 1:
a: x+1/2=5/6
nên x=5/6-1/2=1/3
b: x+1/4=3/4
nên x=3/4-1/4=2/4=1/2
c: x+3/10=1/2
nên x=1/2-3/10=5/10-3/10=1/5
d: x+1/4=3/8
nên x=3/8-1/4=3/8-2/8=1/8
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1/10 + 3/5 : 2/3
=1/10 + 9/10
=10/10
=1
\((\)6/8 -2/6\()\) x 1/2
=18/48 X 1/2
=3/7 x 1/2
=2/14
\(\dfrac{1}{10}\) + \(\dfrac{3}{5}\):\(\dfrac{2}{3}\)
= \(\dfrac{1}{10}\) + \(\dfrac{3}{5}\) \(\times\) \(\dfrac{3}{2}\)
= \(\dfrac{1}{10}\) + \(\dfrac{9}{10}\)
= \(\dfrac{10}{10}\)
= 1
( \(\dfrac{6}{8}\) - \(\dfrac{2}{6}\)) \(\times\) \(\dfrac{1}{2}\)
=( \(\dfrac{18}{24}\) - \(\dfrac{8}{24}\)) \(\times\) \(\dfrac{1}{2}\)
= \(\dfrac{10}{24}\) \(\times\) \(\dfrac{1}{2}\)
= \(\dfrac{5}{24}\)
\(\dfrac{5}{2}+\dfrac{1}{4}.\dfrac{1}{8}\)
\(=\dfrac{5}{2}+\dfrac{1}{32}=\dfrac{5.16+1}{32}=\dfrac{80+1}{32}=\dfrac{81}{32}\)
\(\dfrac{5}{2}\) + \(\dfrac{1}{4}\) x \(\dfrac{1}{8}\)
= \(\dfrac{5}{2}\) + \(\dfrac{1}{32}\)
= \(\dfrac{80}{32}\) + \(\dfrac{1}{32}\)
= \(\dfrac{81}{32}\)