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(x-5)(x-7)=0
=> x-5=0 hoặc x-7=0
=> x=5 hoặc x=7
541+(218-x)=735
=> 218-x=735-541
=> 218-x=194
=> x=218-194
=> x=24
96-3(x+1)=42
=>3(x+1)=96-42
=>3(x+1)=54
=>x+1=54:3
=>x+1=18
=>x=18-1
=>x=17
(x-47)-115=0
=>x-47=0+115
=>x-47=115
=>x=115+47
=>x=162
(x-36):18=12
=>x-36=12.18
=>x-36=216
=>x=216+36
=>x=252
(x-5).(x-7)=0
x-5=0+7
x=7+5
x=12
541+(218-x)=735
218-x=735-541
x=218-196
x=12
96-3(x+1)=42
3(x+1)=96-42
x+1=54:3
x=17-1
x=16
(x-47)-115=0
x-47=0+115
x=115+47
x=162
(x-36):12=18
x-36=12*18
x-36=216
x=216+36
x=252
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a, 541 + ( 218 - x ) = 735
=> 218 - x = 735 - 541
=> 218 - x = 194
=> x = 218 - 194
=> x = 24
Vậy x = 24
b, 96 - 3.( x + 1 ) = 42
=> 3.( x + 1 ) = 96 - 42
=> 3.( x + 1 ) = 54
=> x + 1 = 54 : 3
=> x + 1 = 18
=> x = 18 - 1
=> x = 17
Vậy x = 17
c, ( x - 36 ) : 18 = 12
=> x - 36 = 12.18
=> x - 36 = 216
=> x = 216 + 36
=> x = 252
Vậy x = 252
d, 3x + 3x+1 + 3x+2 = 13.81
=> 3x.1 + 3x.3 + 3x.32= 13.81
=> 3x.( 1 + 3 + 32 ) = 13.81
=> 3x.( 1 + 3 + 9 ) = 13.81
=> 3x.13 = 13.81
=> 3x= 13.81:13
=> 3x= 81
=> 3x = 34
=> x = 4
Vậy x = 4
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Bài 3:
a: Ta có: 60-3(x-2)=51
\(\Leftrightarrow x-2=3\)
hay x=5
b: Ta có: \(4x-20=25:2^2\)
\(\Leftrightarrow4x=\dfrac{25}{4}+20=\dfrac{105}{4}\)
hay \(x=\dfrac{105}{16}\)
c: Ta có: \(8\cdot6+288:\left(x-3\right)^2=50\)
\(\Leftrightarrow288:\left(x-3\right)^2=50-48=2\)
\(\Leftrightarrow\left(x-3\right)^2=144\)
\(\Leftrightarrow\left[{}\begin{matrix}x-3=12\\x-3=-12\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=15\\x=-9\end{matrix}\right.\)
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a) 1254:253= (53)3: (52)3=59:56=53
b) 414:528=414: 52.14=414:(52)14= 414:2514
c) 12n:22n=
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a) 80 - [130 - (12 -4)2 ]
= 80 - ( 130 - 82 )
= 80 - 116
= -36
b) 541 + (218 - b) = 735
218 - b = 194
b = 24
c) 5(x + 35) =515
x+35 = 103
x = 68
d) 96 - 3(x + 1) = 42
3(x+1) = 54
x+1 = 18
x = 17
12x - 33 = 32 . 33
12x - 33 = 243
12x = 276
x = 23
a) Ta có: 541 + (218-x) = 735
=> 218 -x = 735 - 541
=> 218 - x = 194
=> x = 218 - 194
=>x = 16
b;c làm tưởng tự