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1) \(2^x=4^3 \Leftrightarrow2^x=2^6\Leftrightarrow x=6\)
2) \(2^x=4^6\Leftrightarrow2^x=2^{12}\Leftrightarrow x=12\)
3) \(3^x=9^{10}\Leftrightarrow3^x=3^{20}\Leftrightarrow x=20\)
![](https://rs.olm.vn/images/avt/0.png?1311)
Bài 1:
2\(x\) = 4
2\(^x\) = 22
\(x=2\)
Vậy \(x=2\)
Bài 2:
2\(^x\) = 8
2\(^x\) = 23
\(x=3\)
Vậy \(x=3\)
![](https://rs.olm.vn/images/avt/0.png?1311)
a: x^9=x^29
=>x^29-x^9=0
=>x^9*(x^20-1)=0
=>x^9=0 hoặc x^20-1=0
=>x=0; x=1;x=-1
b: x^10=x^7
=>x^7(x^3-1)=0
=>x=0 hoặc x=1
![](https://rs.olm.vn/images/avt/0.png?1311)
Bài 9,
62x73+36x33=36x73+36x27=36(73+27)=36x100=3600.
197-\([\)6x(5-1)2+20220\(]\):5=197-\([\)6x16+1\(]\):5=197-97:5=197-97/5=888/5.
Bài 10,
21-4x=13
=>4x=21-13=8
=>x=8:4=2.
30:(x-3)+1=45:43=42=16
=>30:(x-3)=16-1=15
=>x-3=30:15=2
=>x=2+3=5.
(x-1)3+5x6=38
=>(x-1)3+30=38
=>(x-1)3=38-30=8=23
=>x-1=2
=>x=3.
![](https://rs.olm.vn/images/avt/0.png?1311)
\(a,\Rightarrow x=19-17=2\\ b,\Rightarrow x+8=28:2=14\\ \Rightarrow x=14-8=6\\ c,\Rightarrow42-x=5^2=25\\ \Rightarrow x=42-25=17\)
a)x=2
b)x+8=14
x=6
c)\(42-x=5^2\)
\(42-x=25\)
\(-x=-17\)
\(x=17\)
a)x=1
b)x=1
nha nha nha
a) x=1
b) x=0