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\(a,\dfrac{1}{5}-\dfrac{1}{5}:x=\dfrac{3}{5}\\ \Rightarrow\dfrac{1}{5}:x=\dfrac{1}{5}-\dfrac{3}{5}\\ \Rightarrow\dfrac{1}{5}:x=\dfrac{-2}{5}\\ \Rightarrow x=\dfrac{1}{5}:\dfrac{-2}{5}\\ \Rightarrow x=\dfrac{-1}{2}\)
câu b thiếu đề
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a, | x | + | -5 | = | -37 |
I x I + 5 = 37
I x I = 37 - 5
I x I = 32
x = 32 hoặc x = -32
b, | -6 | . | x | = | 54 |
6 . I x I = 54
I x I = 54 : 6
I x I = 9
x = 9 hoặc x = -9
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8x - 10 = 54
8x = 54 + 10
8x = 64
x = 64 : 8
x = 8
Ai tk mình mình tk lại
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a) Ta có: x-43=(35-x)-48
⇔x-43=35-x-48
⇔x-43=-x-13
⇔x-43+x+13=0
⇔2x-30=0
⇔2(x-15)=0
mà 2≠0
nên x-15=0
hay x=15
b) Ta có: 305-x+14=48+(x-23)
⇔319-x=48+x-23
⇔319-x=x+25
⇔319-x-x-25=0
⇔-2x+294=0
⇔-2x=-294
hay x=147
Vậy: x=147
c) Ta có: -(x-6+85)=(x+51)-54
⇔-x+6-85=x+51-54
⇔-x-79=x-3
⇔-x-79-x+3=0
⇔-2x-76=0
⇔-2x=76
hay x=-38
Vậy: x=-38
d) Ta có: -(35-x)-(37-x)=33-x
⇔-35+x-37+x-33+x=0
⇔3x-105=0
⇔3(x-35)=0
mà 3≠0
nên x-35=0
hay x=35
Vậy: x=35
e) Ta có: 13-|x|=|-4|
⇔13-|x|=4
⇔|x|=9
⇔x∈{9;-9}
Vậy: x∈{9;-9}
f) Ta có: |x|-3+6=16
⇔|x|+3=16
⇔|x|=13
hay x∈{-13;13}
Vậy: x∈{-13;13}
g) Ta có: 35-|2x-1|=14
⇔|2x-1|=21
⇔\(\left[{}\begin{matrix}2x-1=21\\2x-1=-21\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}2x=22\\2x=-20\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=11\\x=-10\end{matrix}\right.\)
Vậy: x∈{11;-10}
h) Ta có: |3x-2|+5=9-x
⇔|3x-2|+5-9+x=0
⇔|3x-2|-4+x=0
⇔|3x-2|=0-(-4+x)
⇔|3x-2|=4-x
⇔\(\left[{}\begin{matrix}3x-2=4-x\\3x-2=x-4\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}3x-2-4+x=0\\3x-2-x+4=0\end{matrix}\right.\)\(\Leftrightarrow\left[{}\begin{matrix}4x-6=0\\2x+2=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}4x=6\\2x=-2\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\frac{3}{2}\left(ktm\right)\\x=-1\left(tm\right)\end{matrix}\right.\)
Vậy: x=-1
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\(\left(5-x\right)^3=-64\)
\(\Leftrightarrow\left(5-x\right)^3=\left(-4\right)^3\)
\(\Leftrightarrow5-x=-4\)
\(\Leftrightarrow x=9\)
1)
( 5 - x )3 = - 64
( 5 - x )3 = ( - 4 )3
\(\Rightarrow\)5 - x = - 4
x = 5 - ( - 4 )
x = 5 + 4
x = 9
2)
A = 4 + 42 +43 + 44 + ........ + 499 + 4100
A = 4(4+1) + 43(4+1) + 45(4+1) + ........... + 499(4+1)
A = 4 . 5 + 43 . 5 + 45 . 5 + ............ + 499 . 5
A = 5(4+43 + 45 + ..........+ 499 )
Mà 5 \(⋮\) 5 \(\Rightarrow\) 5(4+43 + 45 + ........ + 499 ) \(⋮\) 5
Vậy A chia 5 dư 0
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