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\(a,\dfrac{1}{5}-\dfrac{1}{5}:x=\dfrac{3}{5}\\ \Rightarrow\dfrac{1}{5}:x=\dfrac{1}{5}-\dfrac{3}{5}\\ \Rightarrow\dfrac{1}{5}:x=\dfrac{-2}{5}\\ \Rightarrow x=\dfrac{1}{5}:\dfrac{-2}{5}\\ \Rightarrow x=\dfrac{-1}{2}\)
câu b thiếu đề
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![](https://rs.olm.vn/images/avt/0.png?1311)
Ta có: \(6xy-8x-3y-2=0\)
\(\Leftrightarrow6xy-3y-8x+4-6=0\)
\(\Leftrightarrow3y\left(2x-1\right)-4\left(2x-1\right)=6\)
\(\Leftrightarrow\left(2x-1\right)\left(3y-4\right)=6\)
\(\Leftrightarrow\left(2x-1\right);\left(3y-4\right)\inƯ\left(6\right)\)
\(\Leftrightarrow\left(2x-1\right)\left(3y-4\right)\in\left\{1;-1;2;-2;3;-3;6;-6\right\}\)
mà 2x-1 lẻ và \(2x-1\ge-1\) \(\forall x\in N\)
nên \(\left(2x-1\right)\in\left\{-1;1;-3;3\right\}\) và \(\left(3y-4\right)\in\left\{2;-2;6;-6\right\}\)
Trường hợp 1:
\(\left\{{}\begin{matrix}2x-1=-1\\3y-4=-6\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}2x=0\\3y=-2\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x=0\\y=-\dfrac{2}{3}\left(loại\right)\end{matrix}\right.\)
Trường hợp 2:
\(\left\{{}\begin{matrix}2x-1=1\\3y-4=6\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}2x=2\\3y=10\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x=1\\y=\dfrac{10}{3}\left(loại\right)\end{matrix}\right.\)
Trường hợp 3:
\(\left\{{}\begin{matrix}2x-1=-3\\3y-4=-2\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}2x=-2\\3y=2\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x=-1\\y=\dfrac{2}{3}\left(loại\right)\end{matrix}\right.\)
Trường hợp 4:
\(\left\{{}\begin{matrix}2x-1=3\\3y-4=2\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}2x=4\\3y=6\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x=2\\y=2\left(nhận\right)\end{matrix}\right.\)
Vậy: (x,y)=(2;2)
![](https://rs.olm.vn/images/avt/0.png?1311)
((8x - 14) : 2 - 2). 31 = 341
(( 8x - 14) : 2 + 2) = 341 : 31
((8x - 14):2 + 2 = 11
((8x - 14) : 2 = 11 - 2
((8x - 14) : 2 = 9
(8x - 14) = 9. 2
8x - 14 = 18
8x = 18 + 14
8x = 32
x = 32 : 8
x = 4
![](https://rs.olm.vn/images/avt/0.png?1311)
a, | x | + | -5 | = | -37 |
I x I + 5 = 37
I x I = 37 - 5
I x I = 32
x = 32 hoặc x = -32
b, | -6 | . | x | = | 54 |
6 . I x I = 54
I x I = 54 : 6
I x I = 9
x = 9 hoặc x = -9
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Lời giải:
$8x=7,8x+25$
$8x-7,8x=25$
$0,2x=25$
$x=25:0,2=125$
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[ ( 8x - 12 ) : 4 ] . 3^3 = 3^6
[ ( 8x - 12 ) : 4 ] = 3^3 = 27
8x - 12 = 27 .4 = 108
8x = 108 + 12 = 120
x = 120 : 8 = 15
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\(5x+x=30\)
\(x\left(5+1\right)=30\)
\(6x=30\)
\(\Leftrightarrow x=5\)
\(8x+2x=100\)
\(x\left(8+2\right)=100\)
\(10x=100\)
\(x=10\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(8x-3x=40\)
\(x\times\left(8-3\right)=40\)
\(x\times5\) \(=40\)
\(x\) \(=40\div5\)
\(x\) \(=8\)
ủng hộ mk nha mọi người
8x - 10 = 54
8x = 54 + 10
8x = 64
x = 64 : 8
x = 8
Ai tk mình mình tk lại
8x-10=54
8x=54+10
8x=64
x=64:8
x=8