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Bài 9,
62x73+36x33=36x73+36x27=36(73+27)=36x100=3600.
197-\([\)6x(5-1)2+20220\(]\):5=197-\([\)6x16+1\(]\):5=197-97:5=197-97/5=888/5.
Bài 10,
21-4x=13
=>4x=21-13=8
=>x=8:4=2.
30:(x-3)+1=45:43=42=16
=>30:(x-3)=16-1=15
=>x-3=30:15=2
=>x=2+3=5.
(x-1)3+5x6=38
=>(x-1)3+30=38
=>(x-1)3=38-30=8=23
=>x-1=2
=>x=3.
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a ) 4 . ( x2 + 1 ) = 0
x2 + 1 = 0 : 4
x2 + 1 = 0
x2 = 0 - 1
x2 = - 1
x2 = - 12 => x = - 1
Vậy x = - 1
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a)xét 2A =2+2^2+2^3+.....+2^2019
-A=1+2+2^2+...+2^2018
A=(2^2019)-1 <2^2019
b)theo câu a ta có A+1=2^2019-1+1=2^2019=2^(x+1)
2019=x+1 =>x=2018
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Nguyễn Khánh Phương
Bài 1 :
a) 149 - ( 35 : x + 3 ) x 17 = 13
( 35 : x + 3 ) x 17 = 149 - 13
( 35 : x + 3 ) x 17 = 136
( 35 : x + 3 ) = 136 : 17
( 35 : x + 3 ) = 8
35 - x = 8 - 3
35 - x = 5
x = 35 - 5
x = 30
b, 121 : 11 − ( 4x + 5 ) : 3 = 4
11 − 4x + 5 : 3 = 4
4x + 5 : 3 = 11 − 4
4x + 5 : 3 = 7
4x + 5 = 7 x 3
4x + 5 = 21
4x = 21 − 5
4x = 16
x = 16 : 4
x = 4
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Bài 1:
2\(x\) = 4
2\(^x\) = 22
\(x=2\)
Vậy \(x=2\)
Bài 2:
2\(^x\) = 8
2\(^x\) = 23
\(x=3\)
Vậy \(x=3\)
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Bài 1:
|x-2|=4-x
ĐK: \(4-x\ge0\Leftrightarrow x\le4\)
Ta có: \(\orbr{\begin{cases}x-2=4-x\\x-2=x-4\end{cases}\Rightarrow\orbr{\begin{cases}2x=6\\0=2\left(loại\right)\end{cases}\Rightarrow}}x=3\left(tm\right)\)
Vậy x = 3
Bài 2:
a, sao có z
b, Vì \(\hept{\begin{cases}\left|2017-x\right|\ge0\\\left|y-x+2018\right|\ge0\end{cases}\Rightarrow\left|2017-x\right|+\left|y-x+2018\right|\ge0}\)
Mà |2017-x|+|y-x+2018|=0
\(\Rightarrow\hept{\begin{cases}\left|2017-x\right|=0\\\left|y-x+2018\right|=0\end{cases}\Rightarrow\hept{\begin{cases}x=2017\\y-2017+2018=0\end{cases}\Rightarrow}\hept{\begin{cases}x=2017\\y=1\end{cases}}}\)
Vậy x=2017,y=1
c, giống b
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\(\text{a) ( x + 1 ) + ( x + 3 ) + ..... + ( x + 99 ) = 0}\)
\(\Rightarrow\left(x+x+x+.....+x\right)+\left(1+3+5+....+99\right)=0\)
\(\text{Ta có :}\)
\(1+3+5+...+99=\frac{\left(99-1\right):2+1.\left(99+1\right)}{2}=2500\)
\(\Rightarrow50x+2500=0\)
\(\Rightarrow50x=-2500\)
\(\Rightarrow x=-50\)
\(x^3=13\times2+2018^0\)
\(\Rightarrow x^3=13\times2+1\)
\(\Rightarrow x^3=27\)
Mà ta thấy 33 = 27
=> x3 = 33
Vậy x = 3
\(x^3=13\cdot2+2018^0\)
\(\Leftrightarrow x^3=26+1\)
\(\Leftrightarrow x^3=27=3^3\)
\(\Leftrightarrow x=3\)
Vậy x=3