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Tìm ƯCLN(24, 36, 60) và BCNN(24, 36, 60)
Ta có: 24 = 3. 23
36 = 32 . 22
60 = 3 . 22 . 5
\(\Rightarrow\) ƯCLN(24, 36, 60) = 3 . 22 = 12
\(\Rightarrow\) BCNN(24, 36, 60) = 32 . 22 . 5 = 180
![](https://rs.olm.vn/images/avt/0.png?1311)
Ta có:
24=2^3x3
36=2^2x3^2
60=2^2x3x5
BCNN(24,36,60)=2^3x3^2x5=360
BC(24,36,60)={0;360;720;1080;...}
![](https://rs.olm.vn/images/avt/0.png?1311)
Ta có :
24 = 3.23 36=22 . 32 60= 3. 22 . 5
ƯCLN (24, 36, 60)=3.22=12
ƯC (24,36,60)= Ư(12)={1;2;3;4;6;12}
![](https://rs.olm.vn/images/avt/0.png?1311)
12 = 22 . 3
30 = 2 . 3 . 5
ƯCLN ( 12 ; 30 ) = 2 . 3 = 6
8 = 23
9 = 32
ƯCLN ( 8 ; 9 ) = 1
8 = 23
12 = 22 . 3
15 = 3 . 5
ƯCLN ( 8 ; 12 ; 15 ) = 1
24 = 23 . 3
16 = 24
8 = 23
ƯCLN ( 24 ; 16 ; 8 ) =23 = 8
![](https://rs.olm.vn/images/avt/0.png?1311)
1)
a) 18 = 2.3²
30 = 2.3.5
ƯCLN(18; 30) = 2.3 = 6
b) 24 = 2³.3
48 = 2⁴.3
ƯCLN(24; 48) = 2³.3 = 24
c) 18 = 2.3²
30 = 2.3.5
15 = 3.5
ƯCLN(18; 30; 15) = 3
d) 24 = 2³.3
48 = 2⁴.3
36 = 2².3²
ƯCLN(24; 48; 36) = 2².3 = 12
2) a) 174 = 18 . 9 + 12
18 = 12 . 1 + 6
12 = 6 . 2
Vậy ƯCLN(174; 18) = 6
b) 124 = 16 . 7 + 12
16 = 12 . 1 + 4
12 = 4 . 3
⇒ ƯCLN(124; 16) = 4
⇒ BCNN(124; 16) = 124 . 16 : 4 = 496
![](https://rs.olm.vn/images/avt/0.png?1311)
24 = 23.3; 60 = 22.3.5
ƯCLN(24; 60) = 22.3 = 12
35 = 5.7; 7 = 7
ƯCLN(35; 7) = 7
24 = 23.3; 23 = 23
ƯCLN(24; 23) =1
35 = 5.7
7 = 7
1 =1
ƯCLN(35; 7; 1) =1
24=23.3
36=22.32
60=22.3.5
=>ƯCLN(24,36,60)=22.3=12