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a/ ta co \(50^{20}=\left(50^2\right)^{10}\)
\(\left(50^2\right)^{10}=2500^{10}< 2550^{10}\)
Hay \(50^{20}< 2550^{10}\)
b/ ta có \(3^{75}=\left(3^3\right)^{25}\)
\(5^{50}=\left(5^2\right)^{25}\)
\(\Rightarrow\left(3^3\right)^{25}=27^{25}\)
\(\Rightarrow\left(5^2\right)^{25}=25^{25}\)
Vay \(3^{75}>5^{50}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(a=2^{100}=\left(2^4\right)^{25}=16^{25}\)
\(b=3^{75}=\left(3^3\right)^{25}=27^{25}\)
\(c=5^{50}=\left(5^2\right)^{25}=25^{25}\)
Vì \(16^{25}< 25^{25}< 27^{25}\)
\(\Rightarrow a< c< b\)
\(a=2^{100},b=3^{75},c=5^{50}\\ \Rightarrow a=30^{85},b=30^{65},c=30^{44}\\ \Rightarrow a>b>c\)
![](https://rs.olm.vn/images/avt/0.png?1311)
Ta có :
\(2^{100}=\left(2^4\right)^{25}=16^{25}\)
\(3^{75}=\left(3^3\right)^{25}=27^{25}\)
\(5^{50}=\left(5^2\right)^{25}=25^{25}\)
Do \(16^{25}< 25^{25}< 27^{25}\)
\(\Rightarrow2^{100}< 5^{50}< 3^{75}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
Ta có 10750=1072x25=(1072)25=1144925
7375=733x25=(733)25=38901725
vì 11449<389017 nên 1144925<38901725
Do đó 10750<737
Nhấn đúng cho mình nha, cam ơn
\(107^{50}72^{75}=\left(2^3\right)^{75}.\left(3^2\right)^{75}=2^{225}.3^{150}\)
=> \(2^{100}.3^{150}
![](https://rs.olm.vn/images/avt/0.png?1311)
a, Ta có: \(\left(\dfrac{1}{2}\right)^{300}=\left[\left(\dfrac{1}{2}\right)^3\right]^{100}=\left(\dfrac{1}{8}\right)^{100}\)
\(\left(\dfrac{1}{3}\right)^{200}=\left[\left(\dfrac{1}{3}\right)^2\right]^{100}=\left(\dfrac{1}{9}\right)^{100}\)
=> \(\left(\dfrac{1}{8}\right)^{100}>\left(\dfrac{1}{9}\right)^{100}\)=> \(\left(\dfrac{1}{2}\right)^{300}>\left(\dfrac{1}{3}\right)^{200}\)
b, Ta có: \(\left(\dfrac{1}{3}\right)^{75}=\left[\left(\dfrac{1}{3}\right)^3\right]^{25}=\left(\dfrac{1}{27}\right)^{25}\)
\(\left(\dfrac{1}{5}\right)^{50}=\left[\left(\dfrac{1}{5}\right)^2\right]^{25}\)\(=\left(\dfrac{1}{25}\right)^{25}\)
Do \(\left(\dfrac{1}{27}\right)^{25}< \left(\dfrac{1}{25}\right)^{25}=>\left(\dfrac{1}{3}\right)^{75}< \left(\dfrac{1}{5}\right)^{50}\)
Kiểm tra lại bài nhé, học tốt!!
![](https://rs.olm.vn/images/avt/0.png?1311)
375= 33. 25= (33)25= 2725
550= 52.25= (52)25= 2525
Vì 27> 25 nên 2725> 2525
=> Vậy 375> 550.
Tick mình nhé!
![](https://rs.olm.vn/images/avt/0.png?1311)
Ta có\(107^{50}=107^{2.25}=\left(107^2\right)^{25}=11449^{25}\)
\(73^{75}=73^{3.25}=\left(73^3\right)^{25}=389017^{25}\)
Vì 11449 < 389017
\(\Rightarrow11449^{25}< 389017^{25}\)
Vậy \(107^{50}< 73^{75}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
Ta có:
\(\left(-5\right)^{30}=\left(-5^3\right)^{10}=\left(-125\right)^{10}=125^{10}\)
\(\left(-3\right)^{50}=\left(-3^5\right)^{10}=\left(-81\right)^{10}=81^{10}\)
Vì \(125^{10}>81^{10}\)
⇒\(\left(-5\right)^{30}>\left(-3\right)^{50}\)
\(\left(-5\right)^{30}\) và \(\left(-3\right)^{50}\)
Ta có: \(\left(-5\right)^{30}=\left[\left(-5\right)^3\right]^{10}=\left(-125\right)^{10}\)
\(\left(-3\right)^{50}=\left[\left(-3\right)^5\right]^{10}=\left(-243\right)^{10}\)
Vì \(\left(-125\right)^{10}< \left(-243\right)^{10}\) nên \(\left(-5\right)^{30}< \left(-3\right)^{50}\)
Ta có 3^75 = (3^3)^25= 9^25
5^50 = (5^2)^25 =-10^25
=) 9<10 =) 3^75 < 5^50
375 > 350