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Bài 1:
a: \(\Leftrightarrow29\left(x-5\right)=3\left(4x-3\right)\)
=>29x-145=12x-9
=>17x=134
=>x=134/17
b: =>2(5-3x)=2x-1
=>10-6x=2x-1
=>-8x=-11
=>x=11/8
c: =>4x-5=2x-2+x
=>4x-5=3x-2
=>x=3
d: =>7(x-5)=3(x+2)
=>7x-35=3x+6
=>4x=41
=>x=41/4
e: =>(2x+5)(x+5)-2x^2=0
=>2x^2+10x+5x+25-2x^2=0
=>15x+25=0
=>x=-5/3
![](https://rs.olm.vn/images/avt/0.png?1311)
a: \(=\dfrac{x+1+1}{x+2}=1\)
b: \(=\dfrac{3x-7+3x+7}{6}=x\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\left(x+2\right)\left(x+3\right)\left(x+4\right)\left(x+5\right)-8=\left(x^2+7x+10\right)\left(x^2+7x+12\right)-8\)
Đặt \(x^2+7x=t\)
\(\left(t+10\right)\left(t+12\right)-8=t^2+22t+120-8\)
\(=t^2+22t+112=\left(t+8\right)\left(t+14\right)\)
Theo cách đặt \(=\left(x^2+7x+8\right)\left(x^2+7x+14\right)\)
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
11)\(\dfrac{3x+1}{x-5}+\dfrac{2x}{x-5}=\dfrac{3x+2x+1}{x-5}=\dfrac{5x+1}{x-5}\)
12)\(\dfrac{4-x^2}{x-3}+\dfrac{2}{x^2-9}=\dfrac{4-x^2}{x-3}+\dfrac{2}{\left(x-3\right)\left(x+3\right)}=\dfrac{\left(4-x^2\right)\left(x+3\right)}{\left(x-3\right)\left(x+3\right)}+\dfrac{2}{\left(x-3\right)\left(x+3\right)}=\dfrac{2+\left(2-x\right)\left(2+x\right)\left(x+3\right)}{\left(x-3\right)\left(x+3\right)}\)
13)
\(\dfrac{3}{4x-2}+\dfrac{2x}{4x^2-1}=\dfrac{3}{2\left(2x-1\right)}+\dfrac{2x}{\left(2x-1\right)\left(2x+1\right)}=\dfrac{3\left(2x+1\right)}{2\left(2x-1\right)\left(2x+1\right)}+\dfrac{2.2x}{2\left(2x-1\right)\left(2x+1\right)}=\dfrac{6x+3+4x}{2\left(2x-1\right)\left(2x+1\right)}=\dfrac{10x+3}{2\left(2x-1\right)\left(2x+1\right)}\)
14)
\(\dfrac{2x+1}{2x-4}+\dfrac{5}{x^2-4}=\dfrac{2x+1}{2\left(x-2\right)}+\dfrac{5}{\left(x-2\right)\left(x+2\right)}=\dfrac{\left(2x+1\right)\left(x+2\right)}{2\left(x-2\right)\left(x+2\right)}+\dfrac{5.2}{2\left(x-2\right)\left(x+2\right)}=\dfrac{2x^2+5x+12}{2\left(x-2\right)\left(x+2\right)}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
a) -4x2 + 8x - 4
= - (4x2 - 8x + 4)
= - (2x - 2)2
b) -x52 + 10 x - 5
= - 5(x2 - 2x + 1)
= - 5(x - 1)2
![](https://rs.olm.vn/images/avt/0.png?1311)
b1:
AMF đồng dạng ABC
tỉ số : AM/AF = AB/AC
AM/MF = AB/BC
AF/FM = AC/CB
MFD đồng dạng CFD
tỉ số : MF/FD= FD/DC
FM/MD = DC/CF
FD/DM = DF/FC
AFB đồng dạng CFB
tỉ số : AB/ BF = BF/FC
AF/AB =BF/ BC
AF / FB = CF/BC
![](https://rs.olm.vn/images/avt/0.png?1311)
Chụp hơi mờ, xem đỡ nhé :v