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a)S1=1 - 2 - 3 + 4 + 5 - 6 - 7 + 8 - 10 + 11+ ................................+ 1996 + 1997 - 1998 - 1999 + 2000 + 2001
= (1 - 2) + (-3 + 4) + (5 - 6) + (-7 + 8) + (-10 + 11) + .........................................+(-1995 + 1996) + (1997 - 1998) + (-1999 + 2000) + 2001
= -1 + 1 - 1 + 1 - 1 + .......................................... + 1 - 1 + 1 + 2001
= 2001-
b) S =101 - 102 - (-103) - 104 - (-105) - 106 - (-107) - 10
= 101 - 102 + 103 - 104 + 105 - 106 + 107 - 10
= (101 - 102) +(103 - 104 ) + (105 - 106) + 107 - 10
= -1 - 1 - 1 - 1 + 107 - 10
= 107 - 14 = 93
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Câu 1:
[(4x+28).3+5.5]:5=35
[(4x+28).3+5.5]=35.5
(4x+28).3+25=175
(4x+28).3=175-25
(4x+28).3=150
4x+28=150:3
4x+28=50
4x=50-28
4x=22
x=22:4
x=5,5
a.\([\)(4x+28).3+5.5\(]\):5=35\(\Leftrightarrow\)4(x+7).3+25=175\(\Leftrightarrow\)4(x+7).3=150\(\Leftrightarrow\)4.(x+7)=50\(\Leftrightarrow\)x+7=\(\frac{25}{2}\)\(\Leftrightarrow\)x=\(\frac{11}{2}\)
b.720:\([\)41-(2x-5)\(]\)=40\(\Leftrightarrow\)41-(2x-5)=18\(\Leftrightarrow\)2x-5=23\(\Leftrightarrow\)x=14
c.3x+8x-30=25\(\Leftrightarrow\)11x=55\(\Leftrightarrow\)x=5
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em ơi chưa có bài em nhé, em chưa tải bài lên lám sao mình giúp được
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c) (x + 9 - 17) - 24 = 11 - (x + 7)
(x + 8) - 24 = 11 - (x + 7)
(x + 8) - 24 = 11 - x - 7
x-8-24=11-x-7
x-8-24=4-x
x -32 = 4 -x
x + x -32 =4
x + x = 4 +32
2x=36
x=18
a) -5x - 25 = 3x + 23
-5x - 32 = 3x + 8
-5x - 3x - 32 = 8
-5x - 3x = 8 +32
-8x = 8+32
-8x = 40
x= -5
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Lời giải:
PT $\Leftrightarrow (\frac{x+1}{2022}+1)+(\frac{x+2}{2021}+1)+...+(\frac{x+23}{2000}+1)=0$
$\Leftrightarrow \frac{x+2023}{2022}+\frac{x+2023}{2021}+...+\frac{x+2023}{2000}=0$
$\Leftrightarrow (x+2023)(\frac{1}{2022}+\frac{1}{2021}+...+\frac{1}{2000})=0$
Dễ thấy tổng trong () luôn dương
$\Rightarrow x+2023=0$
$\Leftrightarrow x=-2023$
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\(25.\left(x+3\right)=250\)
\(x+3=250:25\)
\(x+3=10\)
\(x=10-3\)
\(\Rightarrow x=7\)
Ai Nhanh Giúp Mik Với =-(
5.3.(x - 5) + 8 = 38
=> 15.(x - 5) = 30
=> x - 5 = 2
=> x = 7
vậy_