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![](https://rs.olm.vn/images/avt/0.png?1311)
a) (–2) + (–5) = – (2 + 5) = –7.
So sánh –7 và –5 có: Vì |–7| = 7; |–5| = 5, mà 7 > 5 nên (–7) < (–5).
Vậy (–2) + (–5) < (–5).
b) (–3) + (–8) = – (3 + 8) = –11.
So sánh –10 và –11: Vì |–10| = 10; |–11| = 11; mà 10 < 11 nên (–10) > (–11).
Vậy (–10) > (–3) + (–8) .
![](https://rs.olm.vn/images/avt/0.png?1311)
a) \(\left(-15\right)\cdot\left(10-12\right)=\left[\left(-15\right)\cdot10-\left(-15\right)\cdot12\right]=-150+180=30\)
b) \(\left(-17\right)\cdot10-\left(-3\right)\cdot10=\left[-17-\left(-3\right)\right]\cdot10=\left(-17+3\right)\cdot10=-14\cdot10=-140\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(a,5>0\\b,-3>-7\\c,0>-1\\d,-1<1\\e,10>-15\\f,-5<-1\\g,-10<2\\h,6>-1\)
a, 5 > 0
b, -3 > -7
c, 0 > -1
d, -1 < 1
e, 10 > -15
f, -5 < -1
g, -10 < 2
h, 6 > -1
![](https://rs.olm.vn/images/avt/0.png?1311)
1: \(28\in B\left(2\right)\)
2: \(125\in B\left(5\right)\)
3: \(22\notinƯ\left(3\right)\)
4: \(8\in B\left(4\right)\)
5: \(77\notin B\left(8\right)\)
6: \(49\in B\left(7\right)\)
7: \(666\in B\left(6\right)\)
8; \(6780\in B\left(10\right)\)
![](https://rs.olm.vn/images/avt/0.png?1311)
1,
a,-3/5
b,-1/2
c,19/39
d,1/4
e,-39/40
f,-59/56
2,
a,=
b,<
c,>
d,<
k cho mình nha
a) − 5 7 + − 6 8 = − 5 7 + − 3 4 = − 20 28 + − 21 28 = − 41 28 = − 123 84
− 1 3 = − 28 84
Vậy − 5 7 + − 6 8 < − 28 84
b) 14 20 + 4 − 5 = 7 10 + − 4 5 = 7 10 + − 8 10 = − 1 10
Vậy 14 20 + 4 − 5 = − 1 10