![](https://rs.olm.vn/images/avt/0.png?1311)
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
(3x-y)/(x+y)=3/4
Nhân chéo lên ta dc:
12x-4y=3x+3y <=> 9x=7y
=> x/y=7/9
Ta có : \(\frac{3x-y}{x+y}=\frac{3}{4}\)
=> (3x - y) . 4 = (x + y) . 3
=> 12x - 4y = 3x + 3y
=> 12x - 3x = 3y + 4y
9x = 7y
=> \(\frac{x}{y}=\frac{7}{9}\)
Vậy tỉ số \(\frac{x}{y}\)là \(\frac{7}{9}\)
Nếu đúng thì nhớ **** cho mình nha ^_^ !
![](https://rs.olm.vn/images/avt/0.png?1311)
3x - y/x+y = 3/4
=> 4(3x - y) = 3(x + y)
=> 12x - 4y = 3x + 3y
=> 12x - 3x = 3y + 4y
=> 9x = 7y
=> x/y = 7/9
\(\frac{3x-y}{x+y}=\frac{3}{4}\Rightarrow12x-4y=3x+3y\Leftrightarrow9x-7y=0\Leftrightarrow x=\frac{7y}{9}\)
Khi đó \(\frac{x}{y}=\frac{\frac{7}{9}y}{y}=\frac{7}{9}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\frac{3x-y}{x+y}=\frac{3}{4}\Rightarrow12x-4y=3x+3y\)
\(\Leftrightarrow9x=7y\Leftrightarrow\frac{x}{y}=\frac{7}{9}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\frac{3x-y}{x+y}=\frac{3}{4}\)
\(\Rightarrow\left(3x-y\right).4=\left(x+y\right).3\)
\(\Rightarrow12x-4y=3x+3y\)
\(\Rightarrow12x-3x=3y+4y\)
\(\Rightarrow9x=7y\)
\(\Rightarrow\frac{x}{y}=\frac{7}{9}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
3x-y/y+x=34
=> 3x - y = 34 ( y + x )
=>3x - y = 34y + 34x
=>-35y = 31x
=>x/y = -35/31
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\Rightarrow4\left(3x+5y\right)=x-2y\Rightarrow12x+20y=x-2y\Rightarrow11x=-22y\Rightarrow\frac{x}{y}=\frac{-22}{11}=-2\)
\(\frac{3x+5y}{x-2y}=\frac{1}{4}\)
\(\Rightarrow x-2y=4\left(3x+5y\right)\)
\(\Rightarrow x-2y=12x+20y\)
\(\Rightarrow12x-x=20y+2y\)
\(\Rightarrow11x=22y\)
\(\Rightarrow x=2y\Leftrightarrow\frac{x}{y}=2\)
![](https://rs.olm.vn/images/avt/0.png?1311)
Ta có: (3x-y)/(x+y) = 3/4 =>4(3x-y)=3(x+y)
=>12x-4y=3x+3y
=>12x-3x=3y+4y
=>9x=7y
=>x/y=7/9
vậy x/y=7/9
3x-y/x+y=3/4
=>(3x-y).4=(x+y).3
=>12x-4y=3x+3y
=>9x=7y
=>x/y=7/9
vậy x/y=7/9