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\(\frac{3x-y}{x-y}=\frac{3}{4}\)
<=> 4(3x-y) = 3(x-y)
<=> 12x - 4y = 3x - 3y
<=> 9x = y
<=> \(\frac{x}{y}=9\)
![](https://rs.olm.vn/images/avt/0.png?1311)
3x - y/x+y = 3/4
=> 4(3x - y) = 3(x + y)
=> 12x - 4y = 3x + 3y
=> 12x - 3x = 3y + 4y
=> 9x = 7y
=> x/y = 7/9
\(\frac{3x-y}{x+y}=\frac{3}{4}\Rightarrow12x-4y=3x+3y\Leftrightarrow9x-7y=0\Leftrightarrow x=\frac{7y}{9}\)
Khi đó \(\frac{x}{y}=\frac{\frac{7}{9}y}{y}=\frac{7}{9}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\frac{3x-y}{x+y}=\frac{3}{4}\Rightarrow12x-4y=3x+3y\)
\(\Leftrightarrow9x=7y\Leftrightarrow\frac{x}{y}=\frac{7}{9}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\frac{3x-y}{x+y}=\frac{3}{4}\Rightarrow\left(3x-y\right)4=3\left(x+y\right)\)
=>12x-4y=3x+3y
=>12x-4y=3x+3y
=>12x-3x=3y+4y
=>9x=7y
=>x/y=7/9
vậy x/y=7/9
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![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
Ta có: \(\frac{3x-y}{x+y}\)=\(\frac{3}{4}\)
\(\Leftrightarrow\)4(3x-y)=3(x+y)
\(\Leftrightarrow\)12x-4y=3x+3y
\(\Leftrightarrow\)12x-3x=4x+3y
\(\Leftrightarrow\)9x=7y
\(\Leftrightarrow\)\(\frac{x}{y}\)=\(\frac{7}{9}\)
\(\frac{3x-y}{x+y}=\frac{3}{4}\Leftrightarrow\frac{3x-y}{x+y}+1=\frac{3}{4}+1\Leftrightarrow\frac{4x}{x+y}=\frac{7}{4}.\) Ở vế trái chia cả tử và mẫu cho y , được:
\(\frac{4.\frac{x}{y}}{\frac{x}{y}+1}=\frac{7}{4}\) Suy ra : \(16.\frac{x}{y}=7\left(\frac{x}{y}+1\right)\) Vậy \(9.\frac{x}{y}=7\Leftrightarrow\frac{x}{y}=\frac{7}{9}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
Ta có: \(\frac{3x-y}{x+y}=\frac{3}{4}\)
\(\Rightarrow\frac{3x+3y-4y}{x+y}=\frac{3}{4}\)
\(\Rightarrow3-\frac{4y}{x+y}=\frac{3}{4}\)
\(\Rightarrow\frac{4y}{x+y}=3-\frac{3}{4}=\frac{9}{4}\)
\(\Rightarrow4.4y=9.\left(x+y\right)\)
\(\Rightarrow16y=9y+9x\)
\(\Rightarrow9x=16y-9y=7y\)
\(\Rightarrow\frac{x}{y}=\frac{7}{9}\)
Vậy tỉ số \(\frac{x}{y}=\frac{7}{9}\)
Ta có: (3x-y)/(x+y) = 3/4 =>4(3x-y)=3(x+y)
=>12x-4y=3x+3y
=>12x-3x=3y+4y
=>9x=7y
=>x/y=7/9
vậy x/y=7/9