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a)
\(x^2-3xy\\ \Leftrightarrow x\cdot\left(x-3y\right)\)
b)
\(4x^2-25\\ \Leftrightarrow\left(2x\right)^2-5^2\\ \Leftrightarrow\left(2x-5\right)\cdot\left(2x+5\right)\)
c)
\(x^2-5x-6\\ \Leftrightarrow x^2+x-6x-6\\ \Leftrightarrow x\cdot\left(x+1\right)-6\cdot\left(x+1\right)\\ \Leftrightarrow\left(x+1\right)\cdot\left(x-6\right)\)
a) \(5x^2-10x=5x\left(x-2\right)\)
b) \(x^2-y^2-2x+2y\\ =\left(x^2-y^2\right)-\left(2x-2y\right)\\ =\left(x-y\right)\left(x+y\right)-2\left(x-y\right)\\ =\left(x-y\right)\left(x+y-2\right)\)
c) \(4x^2-4xy-8y^2\\ =\left(4x^2-4xy+y^2\right)-9y^2\\ =\left(2x-y\right)^2-\left(3y\right)^2\\ =\left(2x-y-3y\right)\left(2x-y+3y\right)\\ =\left(2x-4y\right)\left(2x+2y\right)\\ =2\left(x-2y\right)2\left(x+y\right)\\ =4\left(x-2y\right)\left(x+y\right)\)
Phân tích đa thức thành nhân tử
a,\(xy+y^2-x-y\)
=\(\left(xy+y^2\right)-\left(x+y\right)\)
=\(y\left(x+y\right)-\left(x+y\right)\)
=\(\left(x+y\right)\left(y-1\right)\)
b, \(25-x^2+4xy-4y^2\)
=\(-\left(x^2-4xy+4y^2-25\right)\)
=\(-\left[\left(x-2y\right)^2-5^2\right]\)
=\(-\left(x-2y-5\right)\left(x-2y+5\right)\)
a) xy + y2 - x - y
= x(x+y) - (x+y)
= (x+y)(x - 1)
b) 25 - x2 + 4xy - 4y2
= 52 -( x2 - 4xy + 4y2)
Tự làm nha 
a, 9x2-36
=(3x)2-62
=(3x-6)(3x+6)
b, 2x3y-4x2y2+2xy3
=2xy(x2-2xy+y2)
=2xy(x-y)2
c, ab-b2-a+b
=(ab-b2)-(a-b)
=b(a-b)-(a-b)
=(a-b)(b-1)
a) \(9x^2-36=9.\left(x^2-4\right)=9.\left(x^2-2^2\right)=9.\left(x-2\right).\left(x+2\right)\)
b)\(2x^3y-4x^2y^2+2xy^3=2xy\left(x^2+y^2\right)-\left(2xy\right)^2=2xy.\left(x^2+y^2-2xy\right)=2xy.\left(x-y\right)^2\)
c) \(ab-b^2-a+b=a\left(b-1\right)-b.\left(b-1\right)=\left(a-b\right).\left(b-1\right)\)
P/s: Lần đầu tiên làm nên mình không chắc là đúng >> Mới đọc dạng này :))
a) 4x2 – 6x3y – 2x2 + 8x = 2x ( 2x - 3 x\(^2\)y - x + 4 )
b) x2 – 4 – 2xy + y2 = ( x2– 2xy + y2) \(-4\) = ( x - y )\(^2\) - 2\(^2\)
= ( x - y - 2 ) ( x - y + 2 )
c) x3 – 4x2 – 12x +27
= (x\(^3\) + 27 ) - ( 4x\(^2\) + 12x )
= ( x + 3 ) ( x\(^2\) - 3x + 9 ) - 4x ( x + 3)
= ( x + 3 ) ( x\(^2\) - 3x + 9 - 4x )
= ( x + 3 ) ( x\(^2\) - 7x + 9 )
d) 3x2 – 18x + 27 = 3 ( x\(^2\) - 6x + 9 )
1)\(4x^2+32+64\)
\(\Leftrightarrow\left(2x\right)^2+32x+8^2\)
\(\Leftrightarrow\left(2x+8\right)^2\)
2) \(24-3y^2x=3\left(8-y^2x\right)\)
3) \(\left(x-12\right)^2-9\)
\(\Leftrightarrow\left(x-12-9\right)\left(x-12+9\right)\)
\(\Leftrightarrow\left(x-21\right)\left(x-3\right)\)
b1 :
a. =(x-1)(5x-3x)=2x(x-1)
b.=(3x)2 +2.3x.y +y2= (3x + y)2
c. =(x+y+x-y)(x+y-x+y)=2x.2y=4xy
d.=(x3)2-(y3)2= (x3+y3)(x3-y3)
bài 1
a, 5x(x-1) - 3x(x-1)
= (5x-3x)(x-1)
= 2x(x-1)
b, 9x2 + 6xy + y2
= (3x)2 + 2.3x.y + y2
= (3x+y)2
c, (x+y)2 - (x-y)2
= [(x+y)-(x-y)][(x+y)+(x-y)]
= (x+y-x+y)(x+y+x-y)
= 2y.2x
= 4xy
d, x6-y6
= (x3)2 - (y3)2
= (x3-y3)(x3+y3)
1.a)\(20x-5y=5\left(4x-y\right)\)
b)\(5x\left(x-1\right)-3x\left(x-1\right)=\left(5x-3x\right)\left(x-1\right)=2x\left(x-1\right)\)
c)\(x\left(x+y\right)-6x-6y=x\left(x+y\right)-6\left(x+y\right)=\left(x-6\right)\left(x+y\right)\)
d)\(6x^3-9x^2=3x^2\left(2x-3\right)\)
e)\(4x^2y-8xy^2+10x^2y^2=2xy\left(2x-8y+10xy\right)\)
g)\(20x^2y-12x^3=4x^2\left(5y-3x\right)\)
h)\(8x^4+12x^2y-16x^3y^4=4x^2\left(2x^2+12y-16xy^4\right)\)
2.a)\(3x\left(x+1\right)-5y\left(x+1\right)=\left(3x-5y\right)\left(x+1\right)\)
b)\(3x\left(x-6\right)-2\left(x-6\right)=\left(3x-2\right)\left(x-6\right)\)
c)\(4y\left(x-1\right)-\left(1-x\right)=4y\left(x-1\right)+\left(x-1\right)=\left(4y+1\right)\left(x-1\right)\)
d)\(\left(x-3\right)^3+3-x=\left(x-3\right)^3-\left(x-3\right)=\left(x-3\right)\left[\left(x-3\right)^2-1\right]=\left(x-3\right)\left(x-2\right)\left(x-4\right)\)
e)\(7x\left(x-y\right)-\left(y-x\right)=7x\left(x-y\right)+\left(x-y\right)=\left(7x+1\right)\left(x-y\right)\)
h)\(3x^3\left(2y-3z\right)-15x\left(2y-3z\right)^2=3x\left(2y-3z\right)\left[x^2-5\left(2y-3z\right)\right]\)
k)Sai đề: \(3x\left(z+2\right)+5\left(-z-2\right)=3x\left(z+2\right)-5\left(z+2\right)=\left(3x-5\right)\left(z+2\right)\)
l)\(18x^2\left(3+x\right)+3\left(x+3\right)=3\left(x+3\right)\left(6x^2+1\right)\)
m)\(14x^2y-21xy^2+28x^2y^2=7xy\left(2x-3y+4xy\right)\)
n)\(10x\left(x-y\right)-8y\left(y-x\right)=10x\left(x-y\right)+8y\left(x-y\right)=2\left(5x+4y\right)\left(x-y\right)\)
a, Thay x = -2 và y = 1 vào BT, ta được:
\(M=5.\left(-2\right)^2.1+3.\left(-2\right).1-21=20-6-21=-7\)
b, Ta có: \(a^2-a-6=a^2-3a+2a-6=a\left(a-3\right)+2\left(a-3\right)=\left(a-3\right)\left(a+2\right)\)
uy tín