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Em nhân hệ số với hệ số, biến nhân biến (cùng chữ á)
(xo)2 thì đưa về bằng 12
Em tự làm thử nhé, anh sẽ sửa!
![](https://rs.olm.vn/images/avt/0.png?1311)
Thanh niên còn khổ hơn ! Phải đi làm trung thu cho mấy em !
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mình có đáp án rồi, mik cần bài này dười dạng tự luận cơ
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![](https://rs.olm.vn/images/avt/0.png?1311)
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\(1,-\dfrac{1}{2}.\dfrac{4}{7}+\dfrac{5}{14}=-\dfrac{2}{7}+\dfrac{5}{14}\)
\(=\dfrac{1}{14}\)
\(2,\dfrac{1}{2}-\dfrac{3}{4}+2021^0=-\dfrac{1}{4}+1\)
\(=\dfrac{3}{4}\)
\(3,\left(-\dfrac{1}{5}\right)^2+\dfrac{1}{5}-2.\left(\dfrac{-1}{2}\right)^3-\dfrac{1}{2}\)
\(=\dfrac{1}{25}+\dfrac{1}{5}-2.\left(-\dfrac{1}{8}\right)-\dfrac{1}{2}\)
\(=\dfrac{6}{25}-\left(-\dfrac{1}{4}\right)-\dfrac{1}{2}=\dfrac{6}{25}+\dfrac{1}{4}-\dfrac{1}{2}\)
\(=\dfrac{49}{100}-\dfrac{1}{2}=-\dfrac{1}{100}\)
\(4,\left(3-\dfrac{1}{4}+\dfrac{2}{3}\right)^2:2022^0=\left(\dfrac{11}{4}+\dfrac{2}{3}\right)^2:1\)
\(=\dfrac{1681}{144}:1=\dfrac{1681}{144}\)
\(5,\left(\dfrac{3}{7}\right)^0.1^{15}+\dfrac{7}{9}:\left(\dfrac{2}{3}\right)^2-\dfrac{4}{5}\)
\(=1.1+\dfrac{7}{9}:\dfrac{4}{9}-\dfrac{4}{5}\)
\(=1+\dfrac{7}{9}.\dfrac{9}{4}-\dfrac{4}{5}=1+\dfrac{7}{4}-\dfrac{4}{5}\)
\(=\dfrac{11}{4}-\dfrac{4}{5}=\dfrac{39}{20}\)
\(6,\left\{\left[\left(\dfrac{1}{25}-0,6\right)^2:\dfrac{49}{125}\right].\dfrac{5}{6}\right\}-\left[\left(-\dfrac{1}{3}\right)+\dfrac{1}{2}\right]\)
\(=\left\{\left[\left(-\dfrac{14}{25}\right)^2.\dfrac{125}{49}\right].\dfrac{5}{6}\right\}-\dfrac{1}{6}\)
\(=\left[\left(\dfrac{196}{625}.\dfrac{125}{49}\right).\dfrac{5}{6}\right]-\dfrac{1}{6}\)
\(=\left(\dfrac{196.125}{625.49}.\dfrac{5}{6}\right)-\dfrac{1}{6}=\left(\dfrac{49.4.125}{5.125.49}.\dfrac{5}{6}\right)-\dfrac{1}{6}\)
\(=\left(\dfrac{4}{5}.\dfrac{5}{6}\right)-\dfrac{1}{6}=\dfrac{4}{6}-\dfrac{1}{6}=\dfrac{3}{6}=\dfrac{1}{2}\)
\(7,-\dfrac{5}{14}+\dfrac{3}{8}-\dfrac{2}{14}-\dfrac{3}{8}+\dfrac{1}{2}=\left(-\dfrac{5}{14}-\dfrac{2}{14}\right)+\left(\dfrac{3}{8}-\dfrac{3}{8}\right)+\dfrac{1}{2}\)
\(=-\dfrac{1}{2}+\dfrac{1}{2}=0\)
\(8,-\dfrac{3}{17}.\dfrac{2}{3}+\dfrac{2}{3}.\left(\dfrac{-14}{17}\right)=\dfrac{2}{3}.\left[-\dfrac{3}{17}+\left(-\dfrac{14}{17}\right)\right]\)
\(=\dfrac{2}{3}.\left(-1\right)=-\dfrac{2}{3}\)
#\(Cụt\)
#\(yGLinh\)
ko đăng linh tinh
banjc hưa đọc nôi quy ak
thì bạn hãy đọc đi
gọi 113 đi mọi người