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Đề bài:\(5^x\times5^{x+1}\times5^{x+2}\le100...0\left(18\text{ số }10\right):2^{18}\)
Hay có thể viết thế này:\(5^x.5^{x+1}.5^{x+2}\le10^{18}:2^{18}=5^{18}\)
\(\Leftrightarrow5^{x+\left(x+1\right)+\left(x+2\right)}\le5^{18}\)
\(\Leftrightarrow x+\left(x+1\right)+\left(x+2\right)\le18\)
\(\Leftrightarrow3x+3\le18\)
\(\Leftrightarrow3x\le15\Leftrightarrow x\le5\)
![](https://rs.olm.vn/images/avt/0.png?1311)
a: \(=\left\{145-\left[130-10\right]:2\right\}\cdot5\)
\(=\left\{145-60\right\}\cdot5=85\cdot5=425\)
b: \(=100:\left\{250:\left[450-4\cdot125+4\cdot25\right]\right\}\)
\(=\dfrac{100}{250:\left[450-500+100\right]}=\dfrac{100}{250:50}=\dfrac{100}{5}=20\)
c: \(=355-5\cdot\left[64-\left(27-25\right)\right]=355-5\cdot\left[64-2\right]\)
\(=355-310=45\)
![](https://rs.olm.vn/images/avt/0.png?1311)
a,\(5^3.2-100:4+2^3.5\)
= 125 . 2 - 25 + 8 . 5
= 250 - 25 + 40
= 265
b, \(6^2:9+50.2-3^3.3\)
= 36 : 9 + 100 - 27 . 3
= 4 + 100 - 81
= 23
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a, 100 - 7 ( x - 5 ) = 31 + 33
100 - 7 ( x - 5 ) = 31 + 27
100 - 7 ( x - 5 ) = 58
7 ( x - 5 ) = 100 - 58
7 ( x - 5 ) = 42
x - 5 = 42 : 7
x - 5 = 6
=> x = 6 +5
=> x = 11
Vậy x = 11
b, 12 ( x - 1 ) : 3 = 43 + 23
12 ( x - 1 ) : 3 = 64 + 8
12 ( x - 1 ) : 3 = 72
12 ( x - 1 ) = 72 . 3
12 ( x - 1 ) = 216
x - 1 = 216 : 12
x - 1 = 18
=> x = 18 + 1
=> x = 19
Vậy x = 19
c, 24 + 5x = 75 : 73
24 + 5x = 72
24 + 5x = 49
5x = 49 - 24
5x = 25
=> x = 25 : 5
=> x = 5
Vậy x = 5
d, 5x - 206 = 24 . 4
5x - 206 = 16 . 4
5x - 206 = 64
5x = 64 + 206
5x = 270
=> x = 270 : 5
=> x = 54
Vậy x = 54
e, 125 = x3
53 = x3
=> x = 5
Vậy x = 5
g, 64 = x2
82 = x2
=> x = 8
Vậy x = 8
![](https://rs.olm.vn/images/avt/0.png?1311)
Bài 1:
1; 5\(x\) + \(x\) = 39 - 311 : 39
\(x\).(5 + 1) = 39 - 32
\(x.6\) = 39 - 9
\(x.6\) = 30
\(x\) = 30 : 6
\(x\) = 5
Vậy \(x\) = 5
2; 5\(x\) + \(x\) = 150 : 2 + 3
\(x\).(5 + 1) = 75 + 3
\(x.6\) = 78
\(x\) = 78 : 6
\(x\) = 13
Vậy \(x=13\)
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