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\(1,\Leftrightarrow5\left(x+3\right)=100\\ \Leftrightarrow x+3=20\\ \Leftrightarrow x=17\\ 2,\Leftrightarrow2\cdot3^{x+1}=3^{12}\cdot18\\ \Leftrightarrow2\cdot3^{x+1}=3^{12}\cdot2\cdot3^2=3^{14}\cdot2\\ \Leftrightarrow x+1=14\\ \Leftrightarrow x=13\\ 3,\Leftrightarrow\left[{}\begin{matrix}5x+4=14\\5x+4=-14\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=2\\x=-\dfrac{18}{5}\end{matrix}\right.\)
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a: 2x(x+1)-135=-200
=>2(x^2+x)=-65
=>2x^2+2x+65=0
=>x^2+x+32,5=0
=>x^2+x+0,25+32,25=0
=>(x+0,5)^2+32,25=0(vô lý)
b: 4x-5(x-1)+15=13
=>4x-5x+5=-2
=>5-x=-2
=>x=5+2=7
c: 2/3x-1/4=3/5-7/8
=>2/3x=3/5-7/8+1/4=24/40-35/40+10/40=-1/40
=>x=-1/40:2/3=-1/40*3/2=-3/80
d: 1/2(2x-3)+105/2=-137/2
=>1/2(2x-3)=-137/2-105/2=-242/2=-121
=>2x-3=-242
=>2x=-239
=>x=-239/2
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\(5.3^{x+1}=135\)
\(3^{x+1}=135:5\)
\(3^{x+1}=27\)
\(3^{x+1}=3^3\)
\(x+1=3\)
\(x=3-1\)
\(x=2\)
vậy \(x=2\)
\(3^{x+1}=135:5\)
\(3^{x+1}=27\)
\(3^{x+1}=3^3\)
\(x+1=3\)
\(x=2\)
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Lời giải:
1. $(x+2)-2=0$
$x+2=2$
$x=0$
2.
$(x+3)+1=7$
$x+3=7-1=6$
$x=6-3=3$
3.
$(3x-4)+4=12$
$3x-4+4=12$
$3x=12$
$x=12:3=4$
4.
$(5x+4)-1=13$
$5x+4=13+1=14$
$5x=14-4=10$
$x=10:5=2$
5.
$(4x-8)-3=5$
$4x-8=5+3=8$
$4x=8+8=16$
$x=16:4=4$
6.
$3+(x-5)=7$
$x-5=7-3=4$
$x=4+5=9$
7.
$8-(2x-4)=2$
$2x-4=8-2=6$
$2x=6+4=10$
$x=10:2=5$
8.
$7+(5x+2)=14$
$5x+2=14-7=7$
$5x=7-2=5$
$x=5:5=1$
9.
$5-(3x-11)=1$
$3x-11=5-1=4$
$3x=11+4=15$
$x=15:3=5$
10.
$16-(8x+2)=6$
$8x+2=16-6=10$
$8x=10-2=8$
$x=8:8=1$
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\dfrac{-x-27}{27}=\dfrac{2}{3}\Rightarrow-x-27=18\Leftrightarrow x=-45\)
-> chọn B
Ta có:\(5\left(x-1\right)^3=135\Rightarrow\left(x-1\right)^3=27=3^3\)
\(\Rightarrow x-1=3\Rightarrow x=4\)