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\(9.5^x=\left(6+3\right).5^6\)
\(9.5^x=9.5^6\)
\(5^x=5^6\)
\(x=6\)
9.5 mũ x = ( 6 + 3 ) . 5 mũ 6
9.5 mũ 5 = 9.5 mũ 6
5 mũ x = 5 mũ 6
x = 6
a) \(3^6.3^7\) \(=3^{13}\)
b) \(x^{10}:x^6:x\)
\(=x^{10}:x^7\)\(=x^3\)
c) \(a^5.a^9=a^{14}\)
\(a,=3^{6+7}=3^{13}\\ b,=x^{10-6-1}=x^3\\ c,=a^{5+9}=a^{14}\\ d,=2^3\cdot2^{15}\cdot2^{16}=2^{34}\\ e,=5^6\cdot5^5\cdot5^5=5^{16}\\ f,=a^{10+4-12}=a^2\)
Trần Anh Dũng
b) \(720:\left[41-\left(2x-5\right)\right]=2^3.5\)
\(720:\left[41-2x+5\right]=40\)
\(46-2x=720:40\)
\(46-2x=18\)
\(2x=28\)
\(x=14\)
vậy \(x=14\)
a) \(2^x+2-2^x=96\)
\(0^x=96-2\)
\(0^x=94\)
\(\Rightarrow x\in\varnothing\)
vậy \(x\in\varnothing\)
c) \(16^x< 128^4\)
\(2^{4x}< 2^{28}\)
\(\Rightarrow4x< 28\)
\(\Rightarrow x< 7\)
vậy \(x< 7\)
a, Ta có \(2^{x+2}-2^x=96\)
\(\Rightarrow2^x.2^2-2^x=96\)
\(\Rightarrow2^x.\left(2^2-1\right)=96\)
\(\Rightarrow2^x.3=96\)
\(\Rightarrow2^x=32\)
\(\Rightarrow2^x=2^5\)
\(\Rightarrow x=5\)
b, \(720:\left[51-\left(2x-5\right)\right]=2^3.5\)
\(\Rightarrow720:\left[51-\left(2x-5\right)\right]=40\)
\(\Rightarrow\left[51-\left(2x-5\right)\right]=18\)
\(\Rightarrow2x-5=33\)
\(\Rightarrow2x=38\)
\(\Rightarrow x=19\)
c,\(16^x< 128^4\)
\(\Rightarrow\left(2^4\right)^x< \left(2^7\right)^4\)
\(\Rightarrow\left(2^4\right)^x< \left(2^4\right)^7\)
\(\Rightarrow x< 7\)