Câu hỏi của Trần Anh Dũng

Question

a,2^x+2-2^x=96b720:[41-(2x-5)]=2^3.5c,16^x<128^4

Despacito · Accepted Answer

Trần Anh Dũngb) $720:\left[41-\left(2x-5\right)\right]=2^3.5$$720:\left[41-2x+5\right]=40$$46-2x=720:40$$46-2x=18$$2x=28$$x=14$vậy $x=14$a) $2^x+2-2^x=96$$0^x=96-2$$0^x=94$$\Rightarrow x\in\varnothing$vậy $x\in\varnothing$c) $16^x< 128^4$$2^{4x}< 2^{28}$$\Rightarrow4x< 28$$\Rightarrow x< 7$vậy $x< 7$Câu trả lời: Trần Anh Dũngb) $720:\left[41-\left(2x-5\right)\right]=2^3.5$$720:\left[41-2x+5\right]=40$$46-2x=720:40$$46-2x=18$$2x=28$$x=14$vậy $x=14$a) $2^x+2-2^x=96$$0^x=96-2$$0^x=94$$\Rightarrow x\in\varnothing$vậy $x\in\varnothing$c) $16^x< 128^4$$2^{4x}< 2^{28}$$\Rightarrow4x< 28$$\Rightarrow x< 7$vậy $x< 7$

Kaori Miyazono · Answer

a, Ta có $2^{x+2}-2^x=96$$\Rightarrow2^x.2^2-2^x=96$$\Rightarrow2^x.\left(2^2-1\right)=96$$\Rightarrow2^x.3=96$$\Rightarrow2^x=32$$\Rightarrow2^x=2^5$$\Rightarrow x=5$b, $720:\left[51-\left(2x-5\right)\right]=2^3.5$$\Rightarrow720:\left[51-\left(2x-5\right)\right]=40$$\Rightarrow\left[51-\left(2x-5\right)\right]=18$$\Rightarrow2x-5=33$$\Rightarrow2x=38$$\Rightarrow x=19$c,$16^x< 128^4$$\Rightarrow\left(2^4\right)^x< \left(2^7\right)^4$$\Rightarrow\left(2^4\right)^x< \left(2^4\right)^7$$\Rightarrow x< 7$Câu trả lời: a, Ta có $2^{x+2}-2^x=96$$\Rightarrow2^x.2^2-2^x=96$$\Rightarrow2^x.\left(2^2-1\right)=96$$\Rightarrow2^x.3=96$$\Rightarrow2^x=32$$\Rightarrow2^x=2^5$$\Rightarrow x=5$b, $720:\left[51-\left(2x-5\right)\right]=2^3.5$$\Rightarrow720:\left[51-\left(2x-5\right)\right]=40$$\Rightarrow\left[51-\left(2x-5\right)\right]=18$$\Rightarrow2x-5=33$$\Rightarrow2x=38$$\Rightarrow x=19$c,$16^x< 128^4$$\Rightarrow\left(2^4\right)^x< \left(2^7\right)^4$$\Rightarrow\left(2^4\right)^x< \left(2^4\right)^7$$\Rightarrow x< 7$

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