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a) `123 - 27 + 27 + 13 - 123`
`= (123 - 123) + (27 - 27) + 13`
`= 0 + 0 + 13`
`= 13`
`---`
b) `175 + 25 + 13 + 15 - 175 - 25`
`= (175-175)+(25-25)+25+13`
`=0+0+25+13`
`=28`
`---`
c) \(53\times39+47\times39+53\times21+47\times21\)
\(=\text{[}\left(53+47\right)\times39]+\left[\left(53+47\right)\times21\right]\)
\(=\left(100\times39\right)+\left(100\times21\right)\)
\(=3900+2100\)
`=6000`
`---`
d) \(49\times35+49\times16-49\times61\)
`=` \(49\times\left(35+16-61\right)\)
`=` \(49\times\left(-10\right)\)
`=-490`
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-5 + (-37 - 45 + 51) - (-37 + 51)
= -5 - 37 - 45 + 51 + 37 - 51
= - (5 + 45) - (37 - 37) + (51 - 51)
= - 50 - 0 + 0
= - 50
- (15 - 47 + 58) + (15 - 47 ) + 3
= - 15 + 47 - 58 + 15 - 47 + 3
= (-15 + 15) + (47 - 47) - (58 - 3)
= 0 + 0 - 55
= - 55
(53 - 45 - 49) - (53 + 45 - 49)
= 53 - 45 - 49 - 53 - 45 + 49
= (53 - 53) + (-49 + 49) - (45 + 45)
= 0 + 0 - 90
= - 90
13 - 15 + 49 - 13 + 15 - 48
= (13 - 13) + (-15 + 15) + (49 - 48)
= 0 + 0 + 1
= 1
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\(53.\left(51+4\right)+53.\left(49+91\right)+53\\ =53.55+53.140+53.1\\ =53.\left(55+140+1\right)\\ =53.196\\ =10388.\)
\(53\cdot\left(51+4\right)+\left(49+91\right)+53\)
\(=53\cdot55+53\cdot140+53\cdot1\)
\(=53\cdot\left(55+140+1\right)\)
\(=53\cdot196\)
\(=53\cdot\left(200-4\right)\)
\(=53\cdot200+53\cdot4\)
\(=10600-212\)
\(=10388\)
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\(53.51+4+53.49+91+53\)
\(=53.\left(51+49+1\right)+4+91\)
\(=53.101+4+91\)
\(=5353+4+91\)
\(=5448\)
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53.51+51.4+ 53.49+ 53.96+53
= 53.(51+49)+ 53.( 96+4)+ 53
= 53.100+ 53. 100 + 53
= 5300+5300+53
=10600+53
=10653
****
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\(53\cdot\left(51+4\right)+53\cdot\left(49+96\right)+53\)
=\(53\cdot55+53\cdot145+53\cdot1\)
=\(53\cdot\left(55+145+1\right)\)
=\(53\cdot201\)
=10653
nếu Đ thì k cho mk nhá
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`#3107.101107`
\(\text{53 x 51 + 4 + 53 x 49 + 91 + 53}\)
\(=53\times\left(51+49\right)+\left(4+91+53\right)\\ =53\times100+148\\ =5300+148\\ =5448\)
\(\left(-53\right)\cdot49+\left(-49\right)\cdot47\)
\(=49\left(-53-47\right)\)
\(=49\cdot\left(-100\right)\)
\(=-4900\)
(−53)⋅49+(−49)⋅47
(−53)⋅49+(−49)⋅4
=49(−53−47)=49(−53−47)
=49⋅(−100)=49⋅(−100)
=−4900