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a. 59 + 296
= ( 59 + 1 ) + 295
= 60 + 295
= 355
b) 592 + 48
= ( 592 + 8 ) + 40
= 600 + 40
= 640
Các câu sau tương tự
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Ta có:
49 x 62 + 38 x 73 + 31 x 51 x 2 + 19 x 27 x 2
= 49 x 62 + 38 x 73 + 62 x 51 + 38 x 27
= 62 x ( 49 + 51 ) + 38 x ( 73 + 27 )
= 62 x 100 + 38 x 100
= ( 38 + 62 ) x 100
= 100 x 100
= 10 000
49x62+38x73+31x51x2+19x27x2
= 3038+2774+3162+1026
=10000
k cho mk nha bn! :)
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https://hoc24.vn/cau-hoi/a-5x-2x-62-50b-5x-x-150-2-3c-6x-x-511-59-31d-5x-3x-36-334-124x-2x-68-219-216.2785429565572
a: \(\Leftrightarrow7x=35\)
hay x=5
b: \(\Leftrightarrow6x=78\)
hay x=13
![](https://rs.olm.vn/images/avt/0.png?1311)
x-36/18+2.x+5=19+2.(x-1)
x-2+2x+5=19+2x-1.2
3x-2+5=2x-2+19
3x+3=2x+17
3x=2x+14
x=14
\(x-36:18+2.x+5=19+2\left(x-1\right)\)
\(\Leftrightarrow x+2x+5-\frac{36}{18}=19+2\left(x-1\right)\)
\(\Leftrightarrow3x+5-\frac{38}{16}=19+2\left(x-1\right)\)
\(\Leftrightarrow3x+5-2=19+2\left(x-1\right)\)
\(\Leftrightarrow3x+3=19+2\left(x-1\right)\)
\(\Leftrightarrow3x+3=2x+17\)
\(\Leftrightarrow3x=2x+17-3\)
\(\Leftrightarrow3x=2x+14\)
\(\Leftrightarrow3x=2x+14-2x\)
\(\Leftrightarrow x=14\)
=> x = 14
![](https://rs.olm.vn/images/avt/0.png?1311)
1/4 . 2/6 . 3/8 . ... .30/62 .31/64 = 2^x
(1/2 . 1/2).(2/3 . 1/2).(3/4 . 1/2). ... .(30/31 . 1/2).(31/32 . 1/2) = 2^x
(1/2.1/2. ... .1/2).(1/2 . 2/3 . 3/4. ... .30/31 . 31/32) = 2^x
(31 số 1/2)
(1/2)^31. = 2^x
=> 0=x+36
x=0-36
x=-36
Vậy x=-36
Theo mk nghĩ,mk làm đúng nha .Tk cho mk
Để mk sửa phần này một chút
\((\frac{1}{2})^{31}\cdot\frac{1\cdot2\cdot3.....30\cdot31}{2\cdot3\cdot4.....31\cdot32}=2^x\)
\(\frac{1^{31}}{2^{31}}\cdot\frac{1}{32}=2^x\)
\(\frac{1}{2^{31}}\cdot\frac{1}{2^5}=2^x\)
\(\frac{1}{2^{36}}=2^x\)
\(1=2^x\cdot2^{36}\)
\(2^0=2^x+36\)
Rồi bn tự suy luận nha
![](https://rs.olm.vn/images/avt/0.png?1311)
36 < 6\(2x-1\) < 65
62 < 6\(2x-1\) < 65
2 < 2\(x\) - 1 < 5
3 < 2\(x\) < 6
\(\dfrac{3}{2}\) < \(x\) < 6
\(1,5\) < \(x\) < 3
\(x\) = 2
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\left(25\cdot21+25\cdot51\right):36\\ =\left[25\cdot\left(21+51\right)\right]:36\\ =\left(25\cdot72\right):36\\ =1800:36\\ =50\\ \left\{188-\left[33+\left(6^2-7\cdot3\right)\right]\right\}:70\\ =\left\{188-\left[33+\left(36-21\right)\right]\right\}:70\\ =\left[188-\left(33+15\right)\right]:70\\ =\left(188-48\right):70\\ =140:70\\ =2\)
\(\left(x-1\right)\left(15-3x\right)=0\\ \Rightarrow\left[{}\begin{matrix}x-1=0\\15-3x=0\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}x=1\\3x=15\end{matrix}\right.\\ \Leftrightarrow\left[{}\begin{matrix}x=1\\x=5\end{matrix}\right.\)
\(720:\left[41-\left(2x+5\right)\right]=2^3\cdot5=8\cdot5\\ \Rightarrow720:\left[41-\left(2x+5\right)\right]=40\\ \Rightarrow41-\left(2x+5\right)=720:40\\ \Rightarrow41-\left(2x+5\right)=18\\ \Rightarrow2x+5=41-18\\ \Rightarrow2x+5=23\\ \Rightarrow2x=23-5\\ \Rightarrow2x=18\\ \Rightarrow x=18:2\\ \Rightarrow x=9\)
36^x-2=62+19
36^x-2=81
36^x=81+2=83
=> Không có số x nào thỏa mãn .