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\(=\left(4\cdot6\right)^n:\left(2^2\right)^n=4^n\cdot6^n:4^n=6^n\)
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a: \(125^5:25^3=5^{15}:5^6=5^9\)
b: \(27^6:9^3=3^{18}:3^6=3^{12}\)
c: \(4^{20}:2^{15}=2^{40}:2^{15}=2^{45}\)
d: \(24^n:2^{2n}=24^n:4^n=6^n\)
e: \(64^4\cdot16^5:4^{20}=2^{24}\cdot2^{20}:2^{40}=2^4\)
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`@` `\text {Ans}`
`\downarrow`
\(2^n\cdot2^{2n}\cdot2^3=16\)
`\Rightarrow `\(2^{n+2n+3}=2^4\)
`\Rightarrow `\(2^{3n+3}=2^4\)
`\Rightarrow 3n + 3 = 4`
`\Rightarrow 3n = 4 - 3`
`\Rightarrow 3n = 1`
`\Rightarrow n = `\(\dfrac{1}{3}\)
Vậy, \(n=\dfrac{1}{3}\)
2n.22n.23 = 16
23n = 16: 23
23n = 2
3n = 1
n = \(\dfrac{1}{3}\)
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a) 24n + 1 + 3 = 24n . 2 + 3 = (...6) . 2 + 3 = (....2) + 3 = (....5) ⋮ 5
b) 24n + 2 + 1 = 24n . 22 + 1 = (...6) . 4 + 1 = (...4) + 1 = (....5) ⋮ 5
c) 92n+1 + 1 = 92n . 9 + 1 = (...1) . 9 + 1 = (....9) + 1 = (....0) ⋮ 10
Hok tốt
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b) 34n + 1 + 2 = 34n . 3 + 2 = (...1) . 3 + 2 = (....3) + 2 = (....5) ⋮ 5
c) 24n + 1 + 3 = 24n . 2 + 3 = (...6) . 2 + 3 = (....2) + 3 = (....5) ⋮ 5
d) 24n + 2 + 1 = 24n . 22 + 1 = (...6) . 4 + 1 = (...4) + 1 = (....5) ⋮ 5
e) 92n+1 + 1 = 92n . 9 + 1 = (...1) . 9 + 1 = (....9) + 1 = (....0) ⋮ 10
Hok tốt
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\(=\left(2^3\cdot3\right)^n:2^{2n}=2^{3n}\cdot3^n:2^{2n}=2^n\cdot3^n=6^n\)
24n : 22n = 24n : 4n = (24 : 4)n = 6n