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\(\dfrac{\dfrac{22}{15}}{11-x}\) + \(\dfrac{2}{3}\) = \(\dfrac{7}{5}\)
\(\dfrac{\dfrac{22}{15}}{11-x}\) = \(\dfrac{7}{5}\) - \(\dfrac{2}{3}\)
\(\dfrac{\dfrac{22}{15}}{11-x}\) = \(\dfrac{11}{15}\)
11 - \(x\) = \(\dfrac{22}{15}\) : \(\dfrac{11}{15}\)
11 - \(x\) = 2
\(x\) = 11 - 2
\(x\) = 9
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\(\frac{15}{8}\)+\(\frac{7}{12}\)-\(\frac{13}{3}\)x\(\frac{3}{8}\)
=\(\frac{45}{24}\)+\(\frac{14}{24}\)-\(\frac{13}{8}\)
=\(\frac{59}{24}\)-\(\frac{39}{24}\)
=\(\frac{20}{24}\)=\(\frac{5}{6}\)
\(\frac{11}{5}\)+\(\frac{5}{22}\):2+\(\frac{5}{6}\)
=\(\frac{11}{5}\)+\(\frac{5}{44}\)+\(\frac{5}{6}\)
=\(\frac{484}{220}\)+\(\frac{25}{220}\)+\(\frac{5}{6}\)
=\(\frac{509}{220}\)+\(\frac{5}{6}\)
=\(\frac{1527}{660}\)+\(\frac{550}{660}\)
=\(\frac{2077}{660}\)
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5/8x16/7x21/25
=1/1x2/1x3/5
=6/5
11/12:22/30x6/15
=11/12x30/22x6/15
=1/2x1/2x1/2
=1/8
5/8x16/7x21/25
=1/1x2/1x3/5
=6/5
11/12:22/30x6/15
=11/12x30/22x6/15
=1/2x1/2x1/2
=1/8
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A ) 2/17 + 30/46 + 15/17 + 4/49 + 8/23=102/49
B ) 5/8 x ( 19/31 x 8/5 )=19/31
C ) 7/9 x 8/15 x 9/7 x 15/4=2
D ) 11/12 x 24/7 x 21/22=3
nhìu quá nên mk chỉ cho kết quả thôi nha ^-^!!!
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\(a)x+\frac{2}{3}=\frac{5}{6}\)
\(x=\frac{5}{6}-\frac{2}{3}\)
\(x=\frac{5}{6}-\frac{4}{6}=\frac{1}{6}\)
\(b)x-\frac{3}{5}=\frac{2}{7}+\frac{1}{5}\)
\(x=\frac{3}{5}-\frac{17}{35}\)
\(x=\frac{21}{35}-\frac{17}{35}\)
\(x=\frac{4}{35}\)
\(c)x\div\frac{9}{11}=\frac{5}{22}\)
\(x=\frac{5}{22}\times\frac{9}{11}\)
\(x=\frac{45}{242}\)
\(d)\frac{3}{5}\times x=\frac{3}{10}\)
\(x=\frac{3}{10}\div\frac{3}{5}\)
\(x=\frac{1}{2}\)
\(a)\)\(x+\frac{2}{3}=\frac{5}{6}\)
\(x=\frac{5}{6}-\frac{2}{3}\)
\(x=\frac{1}{6}\)
\(b)\)\(x-\frac{3}{5}=\frac{2}{7}+\frac{1}{5}\)
\(x-\frac{3}{5}=\frac{17}{35}\)
\(x=\frac{17}{35}+\frac{3}{5}\)
\(x=\frac{38}{35}\)
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a)\(\frac{27}{5}\text{x}\frac{91}{12}\text{x}\frac{125}{9}\text{x}\frac{96}{13}=\frac{27}{9}\text{x}\frac{91}{13}\text{x}\frac{125}{5}\text{x}\frac{96}{12}=3\text{x}7\text{x}25\text{x}8\)
Đến đây tự tính nha !
b)\(\frac{2539}{35}\text{x}\frac{7}{90}+\frac{561}{35}\text{x}\frac{7}{90}=\frac{7}{90}\text{x}\left(\frac{2539}{35}+\frac{561}{35}\right)=\frac{7}{90}\text{x}\frac{3100}{35}=\frac{3100}{90}\text{x}\frac{7}{35}=\frac{310}{9}\text{x}\frac{1}{5}=\frac{62}{9}\)
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Ta có:
A = 1 + 3 + 5 + 7 +... + 101
A = \(\frac{102.51}{2}=2601\)
M = 16 - 18 + 20 - 22 + 24 - 26 + .. + 64 - 66 + 68
M = ( 16 - 18 ) + ( 20 - 22 ) + ( 24 - 26 ) + ... + ( 64 - 66 ) + 68
M = (- 2 + - 2 + -2 + ... + - 2 ) + 68
M = 25/2 . ( - 2 ) + 68
M = -25 + 68
M = 43
H = ( 1 + 2 + 3 +...+ 99 ) x ( 13 x 15 - 12 x 15 - 15 )
H = ( 1 + 2 + 3 +...+ 99 ) x { (13 - 12 - 1) x 15 }
H = ( 1 + 2 + 3 +...+ 99 ) x 0
H = 0
G = 1 + 2 - 3 - 4 + 5 + 6 - 7 - 8 + 9 + 10 - 11 - 12 + 13 + 14 - ... + 301 + 302
G = ( 1 + 2 ) + ( -3 - 4 ) + ( 5 + 6 ) + ( -7 - 8 ) + ( 9 + 10 ) + ( - 11 - 12 ) + ( 13 + 14 ) -...+ ( 301 + 302 )
G = ( 3 - 7 ) + ( 11 - 15 ) + ( 19 - 23 ) + 27 - ... + 603
G = -4 + - 4 + -4 + 27 - ... + 603
G = 75 x ( -4 ) + 603
G = -300 + 603
G = 303
2.
a) 1 + 2 + 3 + 4 +...+ 99 + 100 + 2 x X = 5052
= > \(\frac{100.101}{2}\)+ 2 x X = 5052
= > 5050 + 2 x X = 5052
= > 2X = 2
= > X = 1
Lời giải:
$\frac{22}{15}:(11-x)+\frac{2}{3}=\frac{7}{5}$
$\frac{22}{15}:(11-x)=\frac{7}{5}-\frac{2}{3}=\frac{11}{15}$
$11-x=\frac{22}{15}: \frac{11}{15}=2$
$x=11-2=9$