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\(\frac{2005\times2007-1}{2004+2005\times2006}\)
=\(\frac{2005\times\left(2006+1\right)-1}{2004+2005\times2006}\)
=\(\frac{2005\times2006+2005\times1-1}{2004+2005\times2006}\)
=\(\frac{2005\times2006+2005-1}{2004+2005\times2006}\)
=\(\frac{2005\times2006+2004}{2004+2005\times2006}\)
Ta thấy tử số và mẫu số giống nhau nên kết quả của biểu thức bằng 1
Li-ke cho mik nhé!
\(\frac{2005.2007-1}{2004+2005.2006}=\frac{2005.\left(2006+1\right)-1}{2004+2005.2006}=\frac{2005.2006+2005.1-1}{2004+2005.2006}=\frac{2005.2006+2004}{2004+2005.2006}=1\)
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\(\dfrac{1}{2001.2003}+\dfrac{1}{2003.2005}+...+\dfrac{1}{2011.2013}\)
\(=\dfrac{1}{2}\left(\dfrac{2}{2001.2003}+\dfrac{1}{2003.2005}+...+\dfrac{1}{2011.2013}\right)\)
\(=\dfrac{1}{2}\left(\dfrac{1}{2001}-\dfrac{1}{2003}+\dfrac{1}{2003}-\dfrac{1}{2005}+...+\dfrac{1}{2011}-\dfrac{1}{2013}\right)\)
\(=\dfrac{1}{2}\left(\dfrac{1}{2001}-\dfrac{1}{2013}\right)=\dfrac{2}{1342671}\)
=1/2.(2/2001.2003+2/2003.2005+.....+2/2011.2013)
=1/2(1/2001-1/2003+1/2003-1/2005+....+1/2011-1/2013)
=1/2(1/2001-1/2013)
=2/1342671
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\(\dfrac{2006\times2007-8}{2005\times2007+1999}\)
= \(\dfrac{\left(2005+1\right)\times2007-8}{2005\times2007+1999}\)
= \(\dfrac{2005\times2007+2007-8}{2005\times2007+1999}\)
= \(\dfrac{2005\times2007+1999}{2005\times2007+1999}\)
= 1
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a) \(\frac{2005\cdot2006-1}{2006\cdot2004+2005}\)
\(=\frac{2004\cdot2006+2006-1}{2006\cdot2004+2005}\)
\(=1\)
b) \(27\left(\frac{171717}{272727}+\frac{373737}{363636}\right)\)
\(=27\left(\frac{17}{27}+\frac{37}{36}\right)\)
\(=27\cdot\frac{17}{27}+27\cdot\frac{37}{36}\)
\(=17+\frac{9\cdot3\cdot37}{9\cdot4}\)
\(=17+27,75=44,75\)
P/s : ko biết câu b có đúng ko nữa
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\(\frac{2006\times2007-2593}{2005\times2006+1419}\)
\(=\frac{2005\times2006+4012-2593}{2005\times2006+1419}\)
\(=\frac{2005\times2006+1419}{2005\times2006+1419}\)
\(=1\)
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M=(2006-1)x(2006+1)=2006x2006-2006+2006-1=2006x2006-1
M=2006x2006-1
N=2006x2006
Vậy M<N
= 1
làm bằng cách nợ hay lời 1