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\(x-\dfrac{1}{4}=1-\dfrac{5}{8}\\ =>x-\dfrac{1}{4}=\dfrac{3}{8}\\ =>x=\dfrac{3}{8}+\dfrac{1}{4}\\ =>x=\dfrac{5}{8}\)
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57 \(\times\) 46 + 57 \(\times\) 54
= 57 \(\times\) ( 46 + 54)
= 57 \(\times\) 100
= 5700
137 + 355 + 63 + 45
= ( 137 + 63) + ( 355 + 45)
= 200 + 400
= 600
215 \(\times\) 48 - 215 \(\times\) 38
= 215 \(\times\) ( 48 - 38)
= 215 \(\times\) 10
= 2150
4 \(\times\) 50 \(\times\) 25
= ( 4 \(\times\) 25) \(\times\) 50
= 100 \(\times\) 50
= 5 000
57×(46+54) =57×100=5700
137+355+63+45=(137+63) +(355+45) =200+400=600
215×48-215×38=215×(48-38) =215×10=2150
4×50×25=(4×25) ×50=100×50=5000
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\(\dfrac{1}{2}+\dfrac{1}{4}+\dfrac{1}{8}+\dfrac{1}{16}+\dfrac{1}{32}+...+\dfrac{1}{x}=\dfrac{127}{256}\)
Đặt VT là A
\(\Rightarrow2A=1+\dfrac{1}{2}+\dfrac{1}{4}+...+\dfrac{2}{x}\)
\(2A-A=\left(1+\dfrac{1}{2}+\dfrac{1}{4}+...+\dfrac{2}{x}\right)-\left(\dfrac{1}{2}+\dfrac{1}{4}+\dfrac{1}{8}+...+\dfrac{1}{x}\right)=\dfrac{127}{256}\)
\(\Leftrightarrow A=1-\dfrac{1}{x}=\dfrac{127}{256}\)
\(\Leftrightarrow\dfrac{1}{x}=\dfrac{129}{256}\)
\(\Rightarrow x=\dfrac{256}{129}\)
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(2+4+...+16+18) x (45 x 3+ 5 x 45 - 90 x 4)
= A x (135 + 225 - 360)
= A x 0
= 0
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0,2×317×7+0,14×3520+33,1×14
=0,2×7×317+1,4×352+331×1,4
=1,4×317+1,4×352+331×1,4
=1,4×(317+352+331)
=1,4×1000
=1400
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C1 : 5/24 x 5/12 x 24
= 5/24 x ( 5/12 x 24 )
= 5/24 x 10
= 50/24
= 25/12
C2 : 5/24 x 5/12 x 24
= ( 5/24 x 24 ) x ( 5/12 )
= 5 x ( 5/12 )
= 25/12
Chúc em học giỏi !!!
Cách 1 : 5/24 x 5/12 x 24 = (5/24 x 24) x 5/12
= 5 x 5/12 = 25/12
Cách 2 : 5/24 x 5/12 x 24 = 5/24 x (5/12 x 24)
= 5/24 x 10 = 25/12
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a: =11/2*4*5/3
=22*5/3
=110/3
b: =30/12-3/12+20/12
=47/12
c: =28/15+5
=28/15+75/15
=103/15
= 450 nhé bn nhớ k cho mình nghe
2*5*45=10*45=450 tk mk nhé