Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
1/2* x+2/3=9/2
1/2 * x = 9/2 - 2/3
1/2 * x= 23/6
x= 23/6 : 1/2
x= 23/6 x 2= 23/3
___
1/2*x-1/3=2/3
1/2*x = 2/3 + 1/3
1/2 * x= 1
x= 1: 1/2
x= 2
____
1/4+3/4:x=3
3/4 : x = 3 - 1/4
3/4 : x= 11/4
x= 11/4 : 3/4
x= 11/3
\(\dfrac{1}{2}\)\(\times\)\(x\) + \(\dfrac{2}{3}\) = \(\dfrac{9}{2}\)
\(\dfrac{1}{2}\)\(\times\)\(x\) = \(\dfrac{9}{2}\) - \(\dfrac{2}{3}\)
\(\dfrac{1}{2}\)\(\times\)\(x\) = \(\dfrac{23}{6}\)
\(x\) = \(\dfrac{23}{6}\):\(\dfrac{1}{2}\)
\(x\) = \(\dfrac{23}{3}\)
\(\dfrac{1}{2}\)\(\times\)\(x\) - \(\dfrac{1}{3}\) = \(\dfrac{2}{3}\)
\(\dfrac{1}{2}\)\(\times\)\(x\) = \(\dfrac{2}{3}\) + \(\dfrac{1}{3}\)
\(\dfrac{1}{2}\times\)\(x\) = 1
\(x\) = 1 : \(\dfrac{1}{2}\)
\(x\) = 2
\(\dfrac{1}{4}\) + \(\dfrac{3}{4}\): \(x\) = 3
\(\dfrac{3}{4}\): \(x\) = 3 - \(\dfrac{1}{4}\)
\(\dfrac{3}{4}\):\(x\) = \(\dfrac{11}{4}\)
\(x\) = \(\dfrac{3}{4}\): \(\dfrac{11}{4}\)
\(x\) = \(\dfrac{3}{11}\)
\(A=\frac{1}{1+2}+\frac{1}{1+2+3}+\frac{1}{1+2+3+4}+...+\frac{1}{1+2+3+...+2009}\)
\(=\frac{1}{\frac{2\cdot\left(1+2\right)}{2}}+\frac{1}{\frac{3\cdot\left(3+1\right)}{2}}+\frac{1}{\frac{4\cdot\left(4+1\right)}{2}}+...+\frac{1}{\frac{2009\cdot\left(2009+1\right)}{2}}\)
\(=\frac{2}{2\cdot3}+\frac{2}{3\cdot4}+\frac{2}{4\cdot5}+...+\frac{2}{2009\cdot2010}\)
\(=2\cdot\left(\frac{1}{2\cdot3}+\frac{1}{3\cdot4}+\frac{1}{4\cdot5}+...+\frac{1}{2009\cdot2010}\right)\)
\(=2\cdot\left(\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+...+\frac{1}{2009}-\frac{1}{2010}\right)\)
\(=2\cdot\left(\frac{1}{2}-\frac{1}{2010}\right)\)
\(=1-\frac{1}{1005}\)
\(=\frac{1004}{1005}\)
1/1+2=3=1/1+2+2=6=1/1+2+3+4=10+3+6=19+1/1+2+3+4=29+3+6+10+19+2009=2076nếu mình làm sai thì nhớ chỉ dùm
nhớ kết bạn với mình nhé
\(\frac{2}{3}+\frac{3}{4}=\frac{17}{12}\)
\(\frac{1}{2}-\frac{1}{4}=\frac{1}{4}\)
\(\frac{2}{5}x\frac{3}{5}=\frac{6}{25}\)
\(\frac{9}{4}>\frac{9}{5}\)
\(\frac{2}{3}+\frac{3}{4}=\frac{8}{12}+\frac{9}{12}=\frac{17}{12}\)
\(\frac{1}{2}-\frac{1}{4}=\frac{2}{4}-\frac{1}{4}=\frac{1}{4}\)
\(\frac{2}{5}\cdot\frac{3}{5}=\frac{6}{25}\)
So sánh \(\frac{9}{4}\)và \(\frac{9}{5}\)
Vì tử số của hai phân số bằng nhau nên ta chỉ xét mẫu số, nếu mẫu số nào lớn hơn thì phân số đó bé hơn.
Vậy \(\frac{9}{4}\)và\(\frac{9}{5}\)mà\(4< 5\)nên\(\frac{9}{4}>\frac{9}{5}\)
a) ( 1/2-1/3-1/6).(1/2+2/3+3/4+...+2017/2018) + 3/4.x = 9/10
0.(1/2+2/3+3/4+...+2017/2018) + 3/4.x = 9/10
0+3/4.x = 9/10
3/4.x = 9/10
x = 9/10: 3/4
x = 6/5
b) x + ( 3/1.3+3/3.5+...+3/13.15) = 11/5
x + 3/2. ( 1-1/3 + 1/3 - 1/5 + ...+ 1/13 - 1/15) = 11/5
x + 3/2. ( 1-1/15) = 11/5
x + 3/2.14/15 = 11/5
x + 7/5 = 11/5
x = 11/5 - 7/5
x = 4/5
a, 2/3+1/2+1/6
=4/6+3/6+1/6
=4/3
b, 5/12+5/6-3/4
=10/24+20/24-18/24
=1/2
c, 1/3*3/5*2/5
=(1*3*2)/(3*5*5)
=2/25
d, 15/16:3/8*3/4
= 15/16*8/3*3/4
= 15/8
a) \(\frac{2}{3}\)+\(\frac{1}{2}\)+\(\frac{1}{6}\) = \(\frac{4}{6}\)+\(\frac{3}{6}\)+\(\frac{1}{6}\) =\(\frac{8}{6}\) =\(\frac{4}{3}\)
b)\(\frac{5}{12}+\frac{5}{6}-\frac{3}{4}\)=\(\frac{5}{12}+\frac{10}{12}-\frac{9}{12}\)=\(\frac{6}{12}\)= \(\frac{1}{2}\)
c) \(\frac{1}{3}\cdot\frac{3}{5}\cdot\frac{2}{5}\) =\(\frac{6}{75}\)=\(\frac{2}{25}\)
25-2 : (3/5-1/2) + (5/2 +1/5 * 1/4 )
= 25 - 2 : 1/10 + (5/2 + 1/20)
= 25 - 20 + 51/20
= 5 + 51/20
= \(5\frac{51}{20}\)
( 3/10+ 4/5 *1/2 ) : (17/9 -4/3 : 3)
= (3/10 + 2/5) : (17/9 - 4/9)
= (-1/10) : 13/9
= -9/130
\(D=\frac{5}{1+2+3}+\frac{5}{1+2+3+4}+...+\frac{5}{1+2+...+100}\)
\(\Rightarrow D=5\left(\frac{1}{1+2+3}+\frac{1}{1+2+3+4}+...+\frac{1}{1+2+...+100}\right)\)
\(\Rightarrow D=5\left(\frac{1}{\frac{4.3}{2}}+\frac{1}{\frac{5.4}{2}}+...+\frac{1}{\frac{101.100}{2}}\right)\)
\(\Rightarrow D=5\left(\frac{2}{3.4}+\frac{2}{4.5}+...+\frac{2}{100.101}\right)\)
\(\Rightarrow D=10\left(\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+...+\frac{1}{100}-\frac{1}{101}\right)\)
\(\Rightarrow D=10\left(\frac{1}{3}-\frac{1}{101}\right)\)
\(\Rightarrow D=\frac{10}{3}-\frac{10}{101}=\frac{980}{303}\)
I don't now
or no I don't
..................
sorry
= 100/51
Từ từ mình trình bày cho nha